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slamgirl [31]
2 years ago
7

A 250-ml sample of na2so4 is reacted with an excess of bacl2. if 5.28 g baso4 is precipitated, what is the molarity of the na2so

4 solution?
Chemistry
1 answer:
Oksanka [162]2 years ago
3 0
To get the molarity you need to follow this equation
                       moles of solute
Molarity (M = -----------------------
                        Liters of solution

But before you apply that equation you need to find the moles of solute and the liters of solution. Follow this equation

Na2SO4 + BaCl2 = BaSO4 + 2 NaCl

Solution

Moles of BaSO4 = 5.28 g 
                               ---------------
                                233.43 g / mol
                             =  0.0226  moles
Moles of NaSO4 = 0.0226 
                  0.0226 mole
Molarity = -----------------
                  0.250 L
              =  0.0905 mol / L

So the answer is 0.0905 mol / L
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When the volume of a gas is changed from 524 cm^3 to ____ cm^3, the temperature will change from 491 K to 297 K .
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V1/T1=V2/T2
524 cm^3/491 K =V2/297K

V2=(524 cm^3*297K)/491 K= 317K
5 0
3 years ago
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Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of –7.2°C. Bromine can be classified as a
andreev551 [17]

Answer:

Pure substance.

Explanation:

7 0
3 years ago
Find the volume of a gas at STP, if its volume is 80.0 mL at 109 kPa and -12.5°C.​
exis [7]

Answer:

= 913.84 mL

Explanation:

Using the combined gas laws

P1V1/T1 = P2V2/T2

At standard temperature and pressure. the pressure is 10 kPa, while the temperature is 273 K.

V1 = 80.0 mL

P1 = 109 kPa

T1 = -12.5 + 273 = 260.5 K

P2 = 10 kPa

V2 = ?

T2 = 273 K

Therefore;

V2 = P1V1T2/P2T1

     = (109 kPa × 80 mL × 273 K)/(10 kPa× 260.5 K)

     <u>= 913.84 mL</u>

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3 years ago
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Using the Hoffman apparatus for electrolysis, a chemist decomposes 2.3 moles of water into its gaseous elements. How many grams
solong [7]

Answer:

2.318032g

Explanation:

-The electrolysis equation of water is written as below:

2H_2O_{(l)}->2H_2_{(g)}+O_2_{(g)}

-The mole ratio of Water to the hydrogen formed is 1:1, therefore 2.3 moles of hydrogen gas is produced.

-Hydrogen's molar mass is 1.00784 grams:

Mass=moles\times molar \ mass\\\\\=2.3\times 1.00784\\\\=2.318032\ g

Hence, 2.318032 grams of hydrogen is produced.

7 0
3 years ago
How molecules of N2 gas can be present in a 2.5 L flask at 50°C and 650 mmHg?
ratelena [41]

Answer:

0.482 ×10²³ molecules

Explanation:

Given data:

Volume of gas = 2.5 L

Temperature of gas = 50°C (50+273 = 323 k)

Pressure of gas = 650 mmHg (650/760 =0.86 atm)

Molecules of N₂= ?

Solution:

PV= nRT

n = PV/RT

n = 0.86 atm × 2.5 L /0.0821 atm. mol⁻¹. k⁻¹. L × 323 k

n = 2.15 atm. L /26.52 atm. mol⁻¹.L

n = 0.08 mol

Number of moles of N₂ are 0.08 mol.

Number of molecules:

one mole = 6.022 ×10²³ molecules

0.08×6.022 ×10²³ = 0.482 ×10²³ molecules

5 0
3 years ago
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