The answer would be 5.5g because you have to subtract 8.2 minus 2.7 and you get 5.5g so basically the answer is C.
Answer:
A
Explanation:
I looked it up and this was the answer for your question
Answer:
1. Cu(s) + 2AgNO₃(aq) ⟶ Cu(NO₃)₂(aq) + 2Ag(s)
2. 50.92 g
3. $8.09
Step-by-step explanation:
1. Balanced equation
Cu(s) + 2AgNO₃(aq) ⟶ Cu(NO₃)₂(aq) + 2Ag(s)
===============
2. Mass of Ag
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 63.55 107.87
Cu + 2AgNO₃ ⟶ Cu(NO₃)₂ + 2Ag
m/g: 15.00
(a) Calculate the moles of Cu
Moles Cu = 15.00 × 1/63.55
Moles Cu = 0.2360 mol Cu
=====
(b) Calculate the moles of Ag
The molar ratio is 2 mol Ag:1 mol H₂O
Moles of Ag = 0.2360 × 2/1
Moles of Ag = 0.4721 mol Ag
======
(c) Calculate the mass of Ag
Mass of Ag = 0.4721 × 107.87
Mass of Ag = 50.92 g Ag
===============
3. Value of Ag
Mass of Ag = 50.92 × 0.0353/1
Mass of Ag = 1.797 oz
Value of Ag = 1.797 ×4.50/1
Value of Ag = $8.09
Alex earns $400 per week.
He gets $150 per car (x).
"x" is the number of cars Alex has sold.
400 + 150x
If he earned $1450 last week, then
400 + 150x = 1450
First, you subtract 400 from both sides.
150x = 1050
Then divide both sides by 150.
x = 7
Therefore, Alex sold 7 cars last week.
hope this helps!
The two weak conductors energy double up to make a good conductor!