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ddd [48]
3 years ago
9

A graduated cylinder approximate as a regular cylinder has a radius of 1.045 CM and a height of 30.4 ATM what is the volume of t

he cylinder in CM to the power of three use 3.1414 round to the nearest 10th
Chemistry
2 answers:
Serga [27]3 years ago
6 0

Answer:

104.6

Explanation:

Nata [24]3 years ago
4 0

Answer:104.6cm^3

Explanation:

V of a cylinder =πr2h

V = pi((1.045cm)^2)(30.48)

V = 104.57cm^3

Explanation:

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7 0
2 years ago
Determine the density of gold if a 475.09g sample occupy a space of 24.6cm^3
Ira Lisetskai [31]

Answer:

The answer is

<h2>19.31 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of gold = 475.09g

volume = 24.6 cm³

The density of the gold is

density =  \frac{475.09}{24 .6}  \\  = 19.3126016...

We have the final answer as

<h3>19.31 g/cm³</h3>

Hope this helps you

6 0
3 years ago
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