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Arturiano [62]
3 years ago
7

Dunkin’ Donuts offers coffee and donuts that are "familiar with a twist"—popular items that are available all the time, and

seasonal specials like pumpkin spice coffee and heart shaped donuts. This "familiar with a twist" approach is an example of which of the four Ps?
Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

Answer: This is an example of Promotion

Step-by-step explanation:

Hi, the four Ps of marketing are : Product, Price, Promotion and Place.

This is an example of Promotion

Hi, the four Ps of marketing are: Product, Price, Promotion, and Place.

This is an example of Promotion

Promotion includes advertising, public relations, and promotional strategy.

In this case, the coffee and donuts that are "familiar with a twist" is an already available product with a season promotion.

This is one type of promotional strategy that is used in marketing.

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Ralph is paid twice per month. His work offers a flexible-spending account to be used for medical expenses. This plan allows Ral
slava [35]
In this question, we're assuming Ralph had 0 in his saving funds to start with.

The glasses cost 1200 dollars.

There are 12 months in a year.

Each month, Ralph is given his check two times, that means that Ralph receives his check 2(12), or 24, times per year.

Divide 1200 (the cost of the glasses) by 24 (the amount of times Ralph is given his check)

1200 / 24
Divide both numerator and denominator by 12
100 / 2
Simplify
50

Ralph should have put 50 dollars per pay check to pay for the glasses.

A is your answer.

Have an awesome day! :)
6 0
3 years ago
Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
3 years ago
Which expression gives the magnitude of the magnetic field in the region c < r2 < b (at e?
BaLLatris [955]

The electric currents and magnetic materials have an effect called magnetic field. This magnetic field is specified with its direction and magnitude. The magnitude is the strength of the field.

the magnetic field at a distance r from a long straight wire carrying current I can be calculated with the equation:

B = μ​​ ​I / 2 pi R​​

where <span>μ​​ is a constant, I is the current and R is the radius. </span>

5 0
3 years ago
Can you please explain how you did it. Thanks!
vivado [14]
Well first you would start by setting up with a proportion.
In total, the girls paid $54+$22= $76
Thus 1 sister contributed $54/$76=x/100
The other sister contributed $22/$76=x/76
For each proportion, cross-multiply and simplify to get the percentage. The percentage will be the x
5 0
3 years ago
Read 2 more answers
Could anyone help me with these questions ASAP?
FrozenT [24]

8 is b because a circle is 360.

5 0
3 years ago
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