Answer:
c
Step-by-step explanation:
vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= - 
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= -
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table
Is 19%i already pass that it was easy
Answer:
Hey there!
The first equation has no solutions, as it is parallel lines.
The second equation has infinitely many solutions, as it is basically the same line, and the two lines intersect at infinite points.
The third equation is just one solution.
Let me know if this helps :)
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