
Here's the solution ~
Let's find the gradient of the shown line, using coordinates of any two points on it, like I'm gonna use (0 , 2) and (1 , -1)
Use the following equation :




Hence, the gradient = -3 for the given line ~
Answer:
Hello the answer is
diameter = 49cm;
radius = diameter/2 = 24.5cm;
circumference = 2πr ≈ 153.94 = 154cm
1 revolution = 154cm
50 revolution = 7700cm = 77m
I hope I am correct. also please mark brainliest
Step-by-step explanation:
Answer:
39/80
Step-by-step explanation: