Add
5
5
to both sides of the equation.
√
2
x
+
13
=
x
+
5
2
x
+
13
=
x
+
5
To remove the radical on the left side of the equation, square both sides of the equation.
(
√
2
x
+
13
)
2
=
(
x
+
5
)
2
(
2
x
+
13
)
2
=
(
x
+
5
)
2
Simplify each side of the equation.
2
x
+
13
=
x
2
+
10
x
+
25
2
x
+
13
=
x
2
+
10
x
+
25
Solve for
x
x
.
x
=
−
2
,
−
6
x
=
-
2
,
-
6
Exclude the solutions that do not make
√
2
x
+
13
−
5
=
x
2
x
+
13
-
5
=
x
true.
x
=
−
2
-0.7 - (-2.5) =
-0.7 + 2.5 =
2.5 - 0.7 = 1.8
1.8 is your answer
hope this helps
Answer: SU = 4(1) + 1 = 5
Step-by-step explanation:
Since T is on segment SU we know the whole is eqaul to the sum of it’s parts.
ST + TU = SU substitute
3x - 1 + 3x = 4x + 1 simplify
6x - 1 = 4x + 1 solve for x
2x = 2
x = 1
ST = 3(1) -1 = 2
TU = 3(1) = 3
SU = 4(1) + 1 = 5
7 raised to power of 1 is 7
Answer is 7
Hope this helps
The common ratio in a geometric sequence is the ratio between 2 consecutive terms:
-8/2=-4,
then the sequence is 2, -8, 32, -128, -512, 2048, ...
let

be the nth term of the sequence, then




.
.
.
so clearly

and, clearly n are integers >0, since we have a 1st term, a second term and so on... of a sequence (we do not have a "zero'th term"!
Answer:
<span>C. an=2(-4)^n-1; all integers where n>0</span>