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Aloiza [94]
3 years ago
7

At a certain temperature the rate of this reaction is second order in with a rate constant of Suppose a vessel contains at a con

centration of . Calculate how long it takes for the concentration of to decrease to . You may assume no other reaction is important. Round your answer to significant digits.
Chemistry
1 answer:
grigory [225]3 years ago
7 0

Answer: The given question is incomplete. The complete question is:

At a certain temperature the rate of this reaction is second order in NH_4OH with a rate constant of 34.1M^{-1}s^{-1} . NH_4OH(aq)\rightarrow NH_3(aq)+H_2O(aq)

Suppose a vessel contains NH_4OH at a concentration of 0.100 M Calculate how long it takes for the concentration of NH_4OH  to decrease to 0.0240 M. You may assume no other reaction is important. Round your answer to 2 significant digits.

Answer: It takes 0.93 seconds  for the concentration  NH_4OH  to decrease to 0.0240 M.

Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

a_0 = initial concentration = 0.100 M

a= concentration left after time t = 0.0240 M

k = rate constant = 34.1M^{-1}s^{-1}

t = time taken for decomposition = ?

\frac{1}{0.0240}=34.1\times t+\frac{1}{0.100}

t=0.93s

Thus it takes 0.93 seconds  for the concentration  NH_4OH  to decrease to 0.0240 M.

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The specific heat capacity of silver is 0.24 J/°C ·g.
kirza4 [7]

Answer:

A) 900 J

B) 27.96 J

C) 1,628 J ≅ 1.63 kJ

Explanation:

The heat absorbed by the metal (silver) - or energy required to heat it -  is calculated as:

heat = mass x Cp x ΔT

Where Cp is the heat capacity (0.24 J/°C ·g) and ΔT is the change in temperature (final T - initial T).

A) Given:

mass = 150.0 g

final T = 298 K = 25°C

initial T = 273 K = 0°C

We calculate the energy in J to raise the temperature:

heat = mass x Cp x (final T - initial T)

       = 150 .0 g x 0.24 J/°C ·g x (25°C - 0°C )

       = 900 J

B) Given:

moles Ag= 1.0 mol

ΔT = 1.08°C

We first calculate the mass of silver (Ag) by multiplying the moles of Ag by the molar mass of Ag (MM = 107.9 g/mol)

mass = moles x MM = 1.0 mol Ag x 107.9 g/mol Ag = 107.9 g

Then, we calculate the heat required:

heat = mass x Cp x ΔT = 107.9 g x 0.24 J/°C ·g x 1.08°C = 27.96 J

C) Given:

heat = 1.25 kJ = 1,250 J

final T = 15.28°C

initial T = 12.08°C

We first calculate the change in temperature:

ΔT = final T - initial T = 15.28°C - 12.08°C = 3.2°C

Then, we calculate the mass of silver:

mass = heat/(Cp x ΔT) = 1,250 J/(0.24 J/°C ·g x 3.2°C) = 1,628 J ≅ 1.63 kJ

6 0
3 years ago
Gold has a density of 19.32 g>cm3. A piece of gold foil is 2.50 cm on each side and 0.100 mm thick. How many atoms of gold ar
Agata [3.3K]

Answer:

The answer to your question is 3.69 x 10²¹ atoms of gold

Explanation:

Data

density = 19.32 g/cm³

dimensions = 2.5 cm x 2.5 cm x 0.1 mm

number of atoms of gold = x

Process

1.- Find the volume of the foil

Volume = length x height x width

Volume = 2.5 x 2.5 x 0.01

Volume = 0.0625 cm³

2.- Calculate the mass of the foil

Density = mass/volume

mass = density x volume

mass = 19.32 x 0.0625

mass = 1.208 g

3.- Calculate the number of atoms

Atomic number of Gold = 197 g

                    197 g -------------------- 6.023 x 10²³ atoms

                      1.208 g ---------------  x

                       x = (1.208 x 6.023 x 10²³)/197

                       x = 3.69 x 10²¹ atoms of gold

5 0
3 years ago
State the difference that may be observed between the solids obtain by evaporating a solution of a solid to dryness or letting i
tresset_1 [31]

Answer:

It well melt.While theother one will dry

Explanation:

3 0
3 years ago
17.42 mL of 0.1M NaOH was needed to reach the endpoint in the titration. How many moles of NaOH are in 17.42 mL of 0.1M NaOH
Varvara68 [4.7K]

Answer:

0.001742moles

Explanation:

1000ml of NaOH contain 0.1moles

17.42ml of NaOH contain (0.1*17.42)/1000 moles

= 0.001742moles

8 0
2 years ago
ANSWER CORRECTLY PLEASE !!!!!!!!!!!! WILL MARK BRAINLIEST !!!!!!!!!!!!!!!!!!!!!!!
Ann [662]

Answer:

Exothermic.

Explanation:

Exothermic is when he leaves the system. A way to remember is the "ex" which is a prefix/root/suffix or something that pretty much means leaving, I think. For example how it's in "Exodus" and "Exit", I think.

Endothermic is when it goes into the system. Similar to "ex" but with inside, I think. For example how it's in "Endoskeleton", I suppose.

6 0
3 years ago
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