All categories

3 years ago

What is the answer ?

Mathematics

1 answer:

Rzqust [24]3 years ago

3 0

Hope This Helped and GOOD LUCK!!!!!!! :D

You might be interested in

Hurry please will give brainlest will follow like and thank and give points please hurry and help.

Molodets [167]

-2y-11=Z

n/4 -5=m

.................

7 0

3 years ago

Please Someone Help me, and do not spam. 15 points for answer and you will be brainliest if you include steps on how to do it!

frosja888 [35]

I hope this helps you

7 0

3 years ago

Read 2 more answers

Please no links or files I need a direct answer.

Hatshy [7]

Answer:

$\text{a. }128\:\mathrm{cm^3},\\\text{b. }4:1,\\\text{c. }179.4\:\mathrm{cm^2};\:44.8\:\mathrm{cm^2}$

Step-by-step explanation:

The volume of a square pyramid is given by $V=\frac{1}{3}\cdot s^2\cdot h$

Since pyramids A and B are similar, their corresponding side lengths are proportion. Since the base edge of B is half that of A's, each dimension of B will be half of A. Since the formula for volume requires the multiplication of three dimensions, the volume of pyramid A will be $2^3=8$ times larger than the volume of pyramid B.

Thus, the volume of pyramid A is equal to $16\cdot 8=\boxed{128\:\mathrm{in^3}}$ . You can also find the dimensions of pyramid A and use the formula.

The surface area consists of the sum of all areas of the 2D shapes that make the figure. Since all dimensions of pyramid A are twice the dimensions of pyramid B, the ratio of the surface area of pyramid A to pyramid B is $2^2:1=\boxed{4:1}$

The surface area of a square pyramid can be found by adding the areas of the three triangles and one square that make it up. As one long messy formula, that becomes $2s\sqrt{\left(\frac{s}{2}\right)^2+h^2}+s^2$ for a square pyramid with base edge $s$ and height $h$ .

Plugging in values, we get the following:

$A_a\approx \boxed{179.4\:\mathrm{cm^2}},\\A_b\approx \boxed{44.8\:\mathrm{cm^2}}$

5 0

3 years ago

Triangle

sertanlavr [38]

Answer:

Step-by-step explanation:

worng worng

6 0

3 years ago

What is the value of b that makes the lines, given by 3x-y=4 and 2y+4bx=1, perpendicular?

USPshnik [31]

b = 1/6

Explanation:

3x-y=4 ...1st equation

Rewriting in slope- intercept form:

y = 3x - 4

2y+4bx=1

Rewriting in slope- intercept form:

2y = -4bx + 1

y = -4bx/2 + 1/2

Equation of line: y = mx + c

where m = slope, c = intercept

For a line to be perpendicular to another, the slope of one will be the negative reciprocal of the slope of another.

Slope of the 1st equation = 3

m = 3

reciprocal of 3 = 1/3

negative reciprocal of 3 = -1/3

Slope of the 2nd equation = -4b/2

we equate both slope:

negative reciprocal of 3 = -4b/2

-1/3 = -4b/2

cross multiply:

-1(2) = 3(-4b)

-2 = -12b

Divide both sides by -12:

-2/-12 = -12b/-12

b = 1/6

Hence, the value of b that makes the lines perpendicular is 1/6

6 0

11 months ago