Y=-4x+1 you can find this out quickly by doing rise over run count how many blocks go horizontally then go up from that point
B. 24x+27. You multiply everything out and add the x's
Answer:
Given that, Vasudevan invested ₹ 60,000
For Compound Interest (C.I.)
A = P[1 + (r/100)]n
P = ₹ 60,000
n = 6 months and 1 year
R = 12% p.a. compounded half-yearly
where , A = Amount, P = Principal, n = Time period and R = Rate percent
(i) For easy calculation of compound interest, we will put Interest Rate as 6% half-yearly and n = 1.
Compound Interest to be paid for 6 months
A = P[1 + (r/100)]n
A = 60000[1 + (6/100)]1
A = 60000[(100/100) + (6/100)]
A = 60000 × (106/100)
A = 60000 × 1.06
A = ₹ 63600
(ii) Compound Interest to be paid for 12 months (1 year) compounded half yearly.
So, assume n = 2, r = 6%
A = P[1 + (r/100)]n
A = 60000[1 + (6/100)]2
A = 60000[(100/100) + (6/100)]2
A = 60000 × (106/100) × (106/100)
A = 60000 × (11236/10000)
A = 60000 × 1.1236
A = ₹ 67416
The equation x+3=9 is true if and only if x=6.
A bioconditional statement is always written in the “if and only if” form
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)
your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°
-> insert those values, with c substituted with b+3 to remove c
c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE
DE=CE+3=36+3=39
