All categories

3 years ago

Graph the function represented in the table on the coordinate plane.

Mathematics

1 answer:

shusha [124]3 years ago

8 0

Answer:

Try using this method

Step-by-step explanation:

y = -4 - -6 =

-- ----------

x = -1 - -2 =

You might be interested in

What is the solution for -6x-17=19?

Sauron [17]

x = −6 would be your answer

3 0

3 years ago

Read 2 more answers

Please help I don’t understand this.

tresset_1 [31]

The average rate of change of g(x) over the interval [2, 8] is given by

(g (8) - g (2)) / (8 - 2)

In other words, it's the slope of the line through the points (2, g (2)) and (8, g (8)).

Use the definition of the function to evaluate it at the points in the numerator:

• 8 ≥ 4, so using the second piece, g (8) = -0.5(8) + 8 = 4

• 2 < 4, so g (2) = 5(2) + 1 = 11

Then the average rate of change is

(g (8) - g (2)) / (8 - 2) = (4 - 11) / 6 = -7/6

3 0

3 years ago

Which number is a prime number? 63 65 67 69

Romashka-Z-Leto [24]

67 is a prime number

8 0

3 years ago

ryan takes a 30 centimeter by 72 centimeter sheet of paper and cuts from one corner of the paper to diagonally opposite corner.

nikklg [1K]

Answer:

178

Step-by-step explanation:

Use Pythagorean Theorem to find the Hypotenuse

30^2+72^2=78^2

Use perimeter formula

a+b+c

38+72+30

3 0

3 years ago

Read 2 more answers

Assume that there is a 4% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

kap26 [50]

Answer:

a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

4% rate of disk drive failure in a year.

This means that 96% work correctly, $p = 0.96$

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 2$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984$

99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 4$