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DENIUS [597]
3 years ago
15

Please Help!

Chemistry
2 answers:
Nimfa-mama [501]3 years ago
4 0
A. group of rats being tested
b. group of rats not being tested
c. independent variable is what you change (blood pressure medicine)
d. dependent variable depends on what the independent variable does (outcome of testing the rats)
Brilliant_brown [7]3 years ago
4 0

Answer: a. Group of rats which was tested.

b. Group of rats which was left untreated.

c. The new blood pressure medicine.

d. Effectiveness of the blood pressure medicine on the rats.

Explanation:

In an experimental setup certain variables are taken which are examined to determine the result of the experiment. The independent variable can be manipulated in an experiment so as to determine it's influence over the experimental group. The experimental group is the one which is being treated in an experiment. The control group is the one which is not treated in an experiment. It is kept as a standard to observe and compare the changes occurring in the experimental variable. The outcome of the changes occurring in the experimental variable can be used to determine the result of the experiment, in form of dependent variable.

a. Group of rats which was tested.: One group of rats can be used to test the effectiveness of the medicine will be included as experimental group.

b. Group of rats which was left untreated.: One group of rats can be used as a control group which is left undisturbed without treatment.

c. The new blood pressure medicine.: The new blood pressure medicine is the independent variable as it's affect and efficiency is undetermined for blood pressure.

d. Effectiveness of the blood pressure medicine on the rats.: The outcome of drug testing should be the determination of the effectiveness of the medicine on the blood pressure of rats. Hence, this is the dependent variable.

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A sample of O2(g) is placed in an otherwise empty, rigid container at 4224 K at an initial pressure of 4.97 atm, where it decomp
frutty [35]

Answer:

The value of K_p at 4224 K is 314.23.

Explanation:

O_2(g)\rightleftharpoons 2O(g)

Initially

4.97 atm            0

At equilibrium

4.97 - p               2p

At initial stage, the partial pressure of oxygen gas = =4.97 atm

At equilibrium, the partial pressure of oxygen gas = p_{O_2}=0.28 atm

So, 4.97 - p = 0.28 atm

p = 4.69 atm

At equilibrium, the partial pressure of O gas = p_{O}=2p=2\times 4.69 atm=9.38 atm

The expression of K_p is given as :

K_p=\frac{(p_{O})^2}{(p_{O_2})}

K_p=\frac{(9.38 atm)^2}{0.28 atm}=314.23

The value of K_p at 4224 K is 314.23.

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