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Sergio039 [100]
2 years ago
9

15 points + brainliest pls help :(

Chemistry
1 answer:
Komok [63]2 years ago
6 0

Answer:

27 g

Explanation:

M(C6H12O6) = 6*12 + 12*1 + 6*16 = 180 g/mol

100 mL = 0.1 L solution

1.5 M = 1.5 mol/L

1.5 mol/L * 0.1 L = 0.15 mol  C6H12O6

0.15 mol * 180 g/1 mol = 27 g C6H12O6

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When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is
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Answer : The correct option is, (D) 100 times the original content.

Explanation :

As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3

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pH=-\log [H_3O^+]

The hydronium ion concentration at pH = 5.

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The hydronium ion concentration at pH = 3.

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By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.

\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}

100\times [H_3O^+]_{original}=[H_3O^+]_{final}

From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.

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