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TiliK225 [7]
3 years ago
15

Which is the correct answer? (I already tried to do it)

Chemistry
1 answer:
Jet001 [13]3 years ago
4 0
See if it is telling you to add them lol
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Compare Dalton’s and Democritus’ ideas.
Viefleur [7K]

Answer:

please give me brainlist and follow

Explanation:

The key difference between Democritus and Dalton atomic theory is that the Democritus atomic theory is an ancient theory that scientists later refined and elaborated whereas Dalton atomic theory is a comparatively modern, scientific theory that we cannot discard due its important statements.

7 0
3 years ago
4. All of the following are examples of natural causes of air pollution
erma4kov [3.2K]

Answer:

factory emissions

Explanation:

8 0
3 years ago
In the cathode ray tube experiment, J. J. Thomson passed an electric current through different gases inside a cathode ray tube i
Ber [7]

It showed that atoms can be divided into smaller parts.

It showed that all atoms contain electrons.

Explanation:

The experiment carried out by J.J Thomson on the gas discharge tube by passing electric current through a tube filled with many different gases provided a good insight into the structure of an atom.

This experiment led to the development of the plum pudding model of the atom.

  • Cathode rays and it properties were discovered in this set up.
  • It furnished the scientific community with evidences that atoms can be divided into smaller parts.
  • Since atoms now contain some subatomic particles, they can be broken down in like manner into further bits.
  • The cathode rays which were later termed electrons became a fundamental particles known for every atom.

learn more:

Rutherford's model of the atom brainly.com/question/1859083

#learnwithBrainly

6 0
3 years ago
Read 2 more answers
A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s
Alla [95]

<u>Answer:</u> The percent yield of the 1-bromobutane is 48.65 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For NaBr:</u>

Given mass of NaBr = 11.1 g

Molar mass of NaBr = 103 g/mol

Putting values in equation 1, we get:

\text{Moles of NaBr}=\frac{11.1g}{103g/mol}=0.108mol

The chemical equation for the reaction of 1-butanol and NaBr is:

\text{1-butanol + NaBr}\rightarrow \text{1-bromobutane}

By Stoichiometry of the reaction

1 mole of NaBr produces 1 mole of 1-bromobutane

So, 0.108 moles of NaBr will produce = \frac{1}{1}\times 0.108=0.108 moles of 1-bromobutane

  • Now, calculating the mass of 1-bromobutane from equation 1, we get:

Molar mass of 1-bromobutane = 137 g/mol

Moles of 1-bromobutane = 0.108 moles

Putting values in equation 1, we get:

0.108mol=\frac{\text{Mass of 1-bromobutane}}{137g/mol}\\\\\text{Mass of 1-bromobutane}=(0.108mol\times 137g/mol)=14.80g

  • To calculate the percentage yield of 1-bromobutane, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of 1-bromobutane = 7.2 g

Theoretical yield of 1-bromobutane = 14.80 g

Putting values in above equation, we get:

\%\text{ yield of 1-bromobutane}=\frac{7.2g}{14.80g}\times 100\\\\\% \text{yield of 1-bromobutane}=48.65\%

Hence, the percent yield of the 1-bromobutane is 48.65 %

5 0
3 years ago
Which need, want value, or interest was most likely involved in the
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For this question the answer is c
8 0
3 years ago
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