Question

Assuming the gas is at standard temperature and pressure, how many milliliters make up .073 moles of carbon dioxide?

Answer 1

Answer is: 1635 milliliters of carbon dioxide.
n(CO₂) = 0,073 mol.
V(CO₂) = n(CO₂) · Vm.
V(CO₂) = 0,073 mol · 22,4 L/mol.
V(CO₂) = 1,635 L.
V(CO₂) = 1,635 L · 1000 mL/L.
V(CO₂) = 1635 mL.
Vm - molar volume on standard temperature and pressure.

Answer 2

Answer: Volume= 1635.4mL

Explanation:

Using the ideal gas equation

PV= nRT

At standard temperature and pressure

T= 273K P=1.0atm

R= ideal gas constant =0.08206atmL/molk

V=Volume=?

n=0.073mol.

1.0× V = 0.073×0.08206×273

V= 1.6354L

1000mL=1L

Therefore 1.6354L = 1635.4mL