Step-by-step explanation:
Let x = 0.3333333...
Then 10x = 3.3333333....
We have 9x = 3, so x = 3/9 or 1/3.
A. 8.75
B. 0.72
C. 9.31
D. 23.04
E. 6.98
There are 714 boys in that school, you can cross multiply and divide to find the answer, if you wanna check. The way I wrote it was x (boys) / 1309 = 6/11.
Using the normal distribution, it is found that 1851 people would have an IQ less than 115.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:


Z = 1
Z = 1 has a p-value of 0.8413.
Out of 2200 people:
0.8413 x 2200 = 1851.
More can be learned about the normal distribution at brainly.com/question/27643290
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Integration will be ln | ( x /9 ) + (
) | + c .
Given ∫ 1 dx / (
- 81 )
Put ,
x = 9 secθ
dx = 9 secθ tanθ dθ
and
= 9 tanθ
Substituting values in ∫ 1 dx / (
- 81 ) ,
∫ (9 secθ tanθ ) dθ / ( 9 tanθ )
∫ secθ dθ = ln | secθ + tanθ | + c
= ln | ( x /9 ) + (
/ 9 ) | + c
= ln | ( x /9 ) + (
) | + c
Hence , the integration will be ln | ( x /9 ) + (
) | + c .
To learn more on integration follow link :
brainly.com/question/20156869
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