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tankabanditka [31]
3 years ago
13

Your on a roller coaster your velocity is 13 ft./s are you moving up or down what is your speed

Mathematics
1 answer:
vladimir1956 [14]3 years ago
8 0

Your speed is 13 ft/sec.  In order to know our velocity, we would need to know what direction we're moving.  You haven't told us anything about our direction, only that our speed is 13 ft/sec.
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In this equation, y-4/2=10, would i need to get the same denominator<br> y-4/2=10/2 = y-2=5?
Natasha_Volkova [10]
No actually you can just multiply both sides of the equation by 2 and get y-4=20. then add 4 to both sides to get y=24.
3 0
3 years ago
0.34 times 10 with an exponet 3
STALIN [3.7K]

Answer: 340

Step-by-step explanation:

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7 0
2 years ago
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Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
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This is in first person.
3 0
3 years ago
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Value of 1.2^2=1.44
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7 0
2 years ago
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