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2 years ago

Which point is a good approximation of a relative maximum of the graph? O (-2, 0) 0 (-1, -3) (1,3) 0 (2,0) GE

Mathematics

1 answer:

Deffense [45]2 years ago

4 0

Answer: a

Step-by-step explanation: edge

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73.085 in standard form

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3 years ago

If point Cis between points A and B, then AC + CB = <br>A. BC<br>B. ABC <br>C. AB <br>D. CA

omeli [17]

Answer:

C AB

Step-by-step explanation:

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2 years ago

Evaluate the expression. (-3)^-2

Wewaii [24]

$~~(-3)^{-2}\\\\\\=\dfrac 1{(-3)^2}~~~~~~~~~~~~~~~~~~~~~~~~~;\left[k^{-n} = \dfrac 1{k^n},~~~ k \neq 0\right]\\\\\\=\dfrac 1{(-1)^2 \cdot 3^2}\\\\\\=\dfrac 1{1 \times 9}\\\\\\=\dfrac 19$

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1 year ago

Read 2 more answers

If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.

galina1969 [7]

Answer:

$\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ is your average rate of change,

Step-by-step explanation:

average rate of change is

$\frac{f(a+h)-f(a)}{a+h-a}$ , by slope formula

simplify this to get $\frac{f(a+h)-f(a)}{h}$ , which is the definition of the derivative as h goes to 0

$\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}$

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

$\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}$

simplifying

$\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ (your average rate of change)

6 0

2 years ago

5x 10^4 + 2.5 x 10^2 =

professor190 [17]

Answer: 2000000

Step-by-step explanation:

10^4 times 5 times 10^2 =10^6 times 5

5 times 10^6= 5000000

5000000/2.5

=2000000

6 0

2 years ago

Read 2 more answers

Which point is a good approximation of a relative maximum of the graph? O (-2, 0) 0 (-1, -3) (1,3) 0 (2,0) GE​

Which point is a good approximation of a relative maximum of the graph? O (-2, 0) 0 (-1, -3) (1,3) 0 (2,0) GE