12 times with a remainder of 1
The value of (10 1/5) (-5) is -51.
<span><span>2x(x - 5) + 3(x - 5) (rewriting expression)
</span><span>2x(x) - 2x(5) + 3(x) - 3(5) (applying distributive property)
</span><span>2x^2 - 10x + 3x - 15 (simplifying)
</span><span>2x^2 - 7x - 15 (combining like terms)
I found this as an example from research. I do hope this helps. I have trouble in the same subject or I used to anyway. I hope this is what you were looking for. :)</span></span>
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
