Question

When carbonating fruit, the initial partial pressure of CO 2 is 4.00 x 10 – 4 atm, resulting in a concentration of 1.36 x 10 – 5 M . If the partial pressure of CO 2 rises to 0.25 atm, what is the new concentration of CO 2 dissolved?

Answer 1

Answer:

The new concentration of CO₂ dissolved is 0.0085 M

Explanation:

Applying the equation below;

$n = \frac{PV}{K}$

$K= \frac{P_1}{n_1} = \frac{P_2}{n_2}$

where;

P₁ is the initial pressure = 4 x 10⁻⁴ atm

P₂ is the final pressure = 0.25 atm

n₁ is the initial concentration = 1.36 x 10⁻⁵ M

n₂ is the final concentration = ?

n₂ = (n₁*P₂)/(P₁)

n₂ = (1.36 x 10⁻⁵ X 0.25)/(4 x 10⁻⁴)

n₂ = 0.0085 M

Therefore, the new concentration of CO₂ dissolved is 0.0085 M