I need help on question 10 ASAP

Mathematics

1 answer:

Mazyrski [523]4 years ago

4 0

The answer your looking for is 2.6.

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3−2=10 1.k=4 2.k=-4 3.k=36 4.k=-36

asambeis [7]

The answer is number 2, b!

6 0

3 years ago

PLEASE HELP! Will Give brainliest!

statuscvo [17]

Answer:

Step-by-step explanation:

definite integral from 0-2 of root x dx

root x = x^½

integral of x^½ = ⅔x^(3/2)

4 0

2 years ago

There's a photo about it I absolutely know nothing about this question and I really need help

aniked [119]

It’s D
(It’s making me write more words)

4 0

3 years ago

Please help me.. I do not know this. I will give 100 points if you answer.

babunello [35]

Answer:

1) I believe 6 (im wrong I know it)

Step-by-step explanation:

you do whatever like 13902-1 , im so smart

4 0

3 years ago

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

3 years ago