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ziro4ka [17]
3 years ago
11

Carl can buy a 16 ounce package of trail mix for $9.87, or he can make his own trail mix for 65 cent an ounce. Will carl save mo

ney if he buys the 16 ounce package?
Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

Answer:

Carl can save <u>3 cents</u> when he buys a 16 ounce package.

Step-by-step explanation:

Given:

16 ounce package of trial mix = $9.87

1 ounce of trial mix he can make = 65 cents.

We need to find whether Carl will save money if he buys the 16 ounce package.

Solution;

Now we will find the Cost for 1 ounce of trial mix when he buys 16 package of trial mix.

16 ounce package of trial mix = $9.87

1 ounce of trial mix = Cost of 1 ounce of trial mix when a package of 16 ounce of trial mix is bought.

Using Unitary method we get;

Cost of 1 ounce of trial mix when a package of 16 ounce of trial mix is bought. = \frac{9.87}{16}= \$0.62\ \ \ \ Or\ \ \ \  62\ cents

Now from above we can see that;

When a package of 16 ounce of trial mix is brought then 1 ounce of trial mix cost 62 cents while when he prepares his own trial mix the cost of 1 ounce of trial mix is 65 cents.

So we can say that;

Carl can save <u>3 cents</u> when he buys a 16 ounce package.

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bekas [8.4K]

Answer:

  1. reflection across BC
  2. the image of a vertex will coincide with its corresponding vertex
  3. SSS: AB≅GB, AC≅GC, BC≅BC.

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

<h3>1.</h3>

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

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<h3>2.</h3>

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

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<h3>3.</h3>

The markings on the figure show the corresponding parts to be ...

  • side AB and side GB
  • side AC and side GC
  • angle ABC and angle GBC
  • angle BAC and angle BGC

And the reflexive property of congruence tells us BC corresponds to itself:

  • side BC and side BC

There are four available congruence theorems applicable to triangles that are not right triangles

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  • ASA -- two corresponding angles and the side between
  • AAS -- two corresponding angles and the side not between

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

  Corresponding sides are listed above. Here, we list them again:

  AB and GB; AC and GC; BC and BC

SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

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