do you mean 2x squared? If so, x = 5, -5
-π/2 < arctan(x) < π/2
So cos(π/2) < cos(arctan(x)) < cos(0)
0 < cos(arctan(x)) < 1
Area of circle = πr^2
60=πr^2
we need to find radius (r)
so we solve for r
r^2=60/π
r=√(60/π)
r= 4.37
I hope this helps you
x^2+11x+x+36=39+x
x^2+12x+36=39+x
(x+6)^2=39+x
Answer:
ummm i think its B?
Step-by-step explanation:
