(NEED AN URGENT ANSWER) The sum of three consecutive integers is -96. What is the largest integer ?

Mathematics

1 answer:

Ainat [17]3 years ago

5 0

Answer:

-31

Step-by-step explanation:

Let x be the first integer

x+1 is the second integer

x+2 is the third integer

x+ x+1 + x+2 = -96

Combine like terms

3x+3 = -96

Subtract 3 from each side

3x+3-3 = -96-3

3x =-99

Divide by 3

3x/3 = -99/3

x = -33

The integers are

-33

-33+1 = -32

-33+2 = -31

The largest integer is -31

You might be interested in

Given a possible triangle ABC with a=5, b=11, and A=23 degrees, find a possible value for angle b. Round to the nearest tenth.

Stels [109]

<span>b. Round to the nearest tenth. please mark brainly</span>

6 0

3 years ago

PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!

irga5000 [103]

Answer:

None of these.

Step-by-step explanation:

Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.

Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.

In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.

If we look at the first term x^3 and we divide it by 13 we get $\frac{x^3}{13}$ we cannot reduce it so it is not a fraction so 13 is not a factor of P