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goblinko [34]
3 years ago
6

Write this as an equation 4:3=x:y

Mathematics
1 answer:
Sauron [17]3 years ago
7 0
Answer:
4/3 = x/y
3y = 4x
y = 3/4 x
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A rectangle has length 32 inches and its perimeter is 6 times its width. What is its width in inches
professor190 [17]

Answer:

16

Step-by-step explanation:

6x = 2(x + 32)

I hope this helps!

8 0
3 years ago
I need help with this question?????
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(5 cases)/(19/8 hours)
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3 0
3 years ago
Write an equation for a parabola opening upward, shifted 6 units right, and three units down
jolli1 [7]

y = (x-6)²-3

1) Let's write a transformation described as it is, algebraically speaking.

• opening upward, (a >0)

,

• shifted 6 units right, (-6)

,

• and three units down​ -3

2) Starting from the parent function y=x², then we can write:

y = (x-6)²-3

Notice that the horizontal shift is within the parentheses with a swapped sign. And outside that -3 indicating the vertical shift.

5 0
1 year ago
Suppose that is an angleand y is not in the first quadrant. Compute the exact value of secyYou do not have to rationalize the de
Pavel [41]

ANSWER :

The answer is :

-\frac{5\sqrt{10}}{9}

EXPLANATION :

Note that cotangent is only positive when the angle is in the first or third quadrant.

Since y is not in the first quadrant, it must be in the third quadrant.

So the x and y are both negative.

An angle with a terminal point (x, y)

The cotangent is x/y

We can equate :

\cot\gamma=\frac{9}{13}=\frac{x}{y}

Since x and y are both negatives, x = -9 and y = -13

We can have the triangle :

The hypotenuse will be :

\begin{gathered} c=\sqrt{(-9)^2+(-13)^2} \\ c=5\sqrt{10} \end{gathered}

We are asked to find the value of sec y.

In an angle with a terminal point (x, y)

The secant is :

\sec\gamma=\frac{\text{ hypotenuse}}{x}

The hypotenuse is 5√10 and x = -9

The value of sec will be :

\begin{gathered} \sec\gamma=\frac{5\sqrt{10}}{-9} \\  \\ =-\frac{5\sqrt{10}}{9} \end{gathered}

6 0
1 year ago
Solve each equation for the indicated variable Write down your steps ax + by = c, for y
Irina18 [472]

Answer:

I'm so sorry, there is no equation to be seen in this question. If you could please repost the same question with the equations to solve, I't more than happy to answer it for you! I'll just edit my answer and solve it.

8 0
3 years ago
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