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Vesnalui [34]
2 years ago
11

Drag steps into order to correctly solve the equation 4x = 112 for x.

Mathematics
2 answers:
inessss [21]2 years ago
7 0
112 divided by 4 its equal to 28 so x=28
alekssr [168]2 years ago
5 0
4x=112
x=112/4      ( '/' means divide)
x=28
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The value of y varies directly with x, and y=28 when x=7. Find y when x=4 by first finding k.
lesya692 [45]
Direct proportionality is the type of proportionality where an increase in one quantity or variable causes a corresponding increase in another quantity. 
Therefore; y varies directly as x
Hence; y α x
             y =k x where k is a constant 
if y= 28 and x = 7 , then k = 28/4 =4
hence, y = 4 k
when x = 4, then y= 16

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3 years ago
Frank has a science test on Monday over the weekend she studies 47 7/8 of an hour for each three hours how many minutes does Fra
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Cual es la amplitud de estos conjuntos de datos 12,16,48,64,36,48,12,32,y 48
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Step-by-step explanation:
8 0
2 years ago
A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th
Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let S(t) be the amount of sugar in the tank at time t. Then S(0)=25.

Sugar is added to the tank at a rate of <em>P</em> lb/min, and removed at a rate of

\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}

Separate variables, integrate, and solve for <em>S</em>.

\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt

\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt

-100\ln\left|P-\dfrac S{100}\right|=t+C

\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t

P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}

\dfrac S{100}=P-Ce^{-100t}

S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}

Use the initial value to solve for <em>C</em> :

S(0)=25\implies 25=100P-C\implies C=100P-25

\implies S(t)=100P-(100P-25)e^{-100t}

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick <em>P</em> such that

S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}

5 0
2 years ago
28 elementary schools to 16 middle schools write the ratio in simplest form
AnnyKZ [126]
28 to 16

Divide both numbers by 4.

7 to 4
3 0
3 years ago
Read 2 more answers
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