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jonny [76]
3 years ago
15

An ionic compound has the general form, xcly. which option for x and y correctly completes the formula?

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
8 0
Answer:
Case 1:
            X  =  Any element from Group I
            
                       i)    H
                       ii)   Li
                       iii)  Na
                       iv)  K
                       v)   Rb
                       vi)  Cs

            Y  =  1

Case 2:
            X  =  Any element from Group II
            
                       i)    Be
                       ii)   Mg
                       iii)  Ca
                       iv)  Sr
                       v)   Ba
                       vi)  Ra

            Y  =  2

Case 3:
            X  =  Any element from Group III
            
                       i)    B
                       ii)   Al
                       iii)  Ga
                       iv)  In
                       v)   Ti

            Y  =  3

Explanation:
                   The general formula given is as follow,

                                                    XCly

So, if X has +1 oxidation state, then it will require only one Cl atom with oxidation number -1 to form a neutral compound, therefore, y = 1.

If X has +2 oxidation state, then it will require two Cl atoms with oxidation number -1 to form a neutral compound, therefore, y = 2.

If X has +3 oxidation state, then it will require three Cl atoms with oxidation number -1 to form a neutral compound, therefore, y = 3.
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Atomic number = 42

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Atomic symbol  = Mo

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5 0
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In the titration of wine to determine the acid concentration, 10.0 mL of wine was placed in a beaker and diluted with 40.0 mL of
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Answer:

0.0042 M is the molarity of tartaric acid in this sample of wine.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is tartaric acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL

Putting values in above equation, we get:

2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL

M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M

0.0042 M is the molarity of tartaric acid in this sample of wine.

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