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2 years ago

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Which statement BEST describes what happens during solvation?

1 answer:

Ymorist [56]2 years ago

3 0

Answer:

A

Explanation:

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Write the formula and determine the percent by mass of the salt in barium hydroxide octahydrate *

user100 [1]

Answer:

315.51g/mol

Explanation:

137(33 + (16.00 + 1.01) 2 + 8 [1.01 (2) + 16.00] = 315.51g/mol

7 0

2 years ago

Elements can be described by various properties, and identified by their boiling and melting points. For example, gold melts at

Leni [432]

Answer:

Elements can be described by various properties, and identified by their boiling and melting points. For example, gold melts at

Elements can be described by various properties, and identified by their boiling and melting points. For example, gold melts at 1,064ºC and boils at 2,856ºC. Does boiling point depend on the mass present?

A. No; chemical properties stay the same regardless of mass.

B. No; physical properties stay the same regardless of mass.

C. Yes; physical properties can change when mass increases or decreases.

D. No; qualitative properties like boiling point stay the same regardless of mass.

Explanation:

3 0

1 year ago

Calculate the concentration of h3o⁺ in a solution that contains 5.5 × 10-5 m oh⁻ at 25°c. Identify the solution as acidic

Andreas93 [3]

Answer: $[H_3O^+]=1.6\times 10^{-10}M$ , the solution is basic

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.

$pH=-\log [H_3O^+]$

$pOH=-\log[OH^-]$

Putting in the values:

$pOH=-\log[5.5\times 10^{-5}]$

$pOH=4.2$

$pH+pOH=14$

$pH=(14-pOH)=(14-4.2)=9.8$

$9.8=-\log [H_3O^+]$

$[H_3O^+]=1.6\times 10^{-10}M$

As pH is more than 7, the solution is basic

7 0

2 years ago

What happens when a solid turns straight into a gas?

LiRa [457]

Answer:

The atoms are separating, and sublimation is happening.

Explanation:

5 0

2 years ago

Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1

givi [52]

According to Hasselbach-Henderson equation:

$pH=pK_{a}+log\frac{[A^{-}]}{[HA]}$

Here, $[A^{-}]$ is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is $CH_{3}COOK$ and acid is $CH_{3}COOH$ thus, Hasselbach-Henderson equation will be as follows:

$pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}$ ...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{2}{1}=5.06$

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{3}=4.28$

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{5}{1}=5.45$

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{1}=4.76$

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{10}=3.76$

Therefore, pH of solution is 3.76.

4 0

2 years ago