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LenKa [72]
3 years ago
5

How many moles are there in 35.2g of Gold?

Chemistry
1 answer:
ki77a [65]3 years ago
5 0

Explanation:

196.96655

maybe

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Gamma rays are often used to kill microorganisms in food, in an attempt to make the food safer. Some people contend that this ir
kumpel [21]
<span>While treating food with gamma rays kills microorganism by damaging their DNA, the energy of gamma rays rips off electrons from atoms hence ionizing them (causing free radicals). However, gamma rays do not make the food atoms radioactive. The body has a natural mechanism of riding the body of free radicals. However, large quantities of radicals in the body can cause damage.</span>




7 0
3 years ago
Cecil writes the equation for the reaction of hydrogen and oxygen below.
Wittaler [7]

Answer:

C) to show that atoms are conserved in chemical reactions

Explanation:

When writing a chemical reaction, we should always consider the Mass Conservation Law, which basically states that; in an isolated system; the total mass should remain constant, this is, the total mass of the reactives should be equal to the total mass of the products

For this case, we should add the apporpiate coefficients in order to be in compliance with this law:

2H₂ + O₂ → 2H₂O

So, we can check the above statement:

For reactives (left side):

4H

2O

For product (right side):

4H

2O

5 0
3 years ago
A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to
Drupady [299]

Answer : The final temperature of the mixture is 29.6^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron = 0.499J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron = 39.9 g

m_2 = mass of water  = Density\times Volume=1g/mL\times 50.0mL=50.0g

T_f = final temperature of mixture = ?

T_1 = initial temperature of iron = 78.1^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC

T_f=29.6^oC

Therefore, the final temperature of the mixture is 29.6^oC

8 0
3 years ago
How explain two ways to decrease the energy of a wave
Aleks04 [339]

Answer:

gravity that's what I rellat think it is

3 0
3 years ago
What are the properties of salt
GrogVix [38]
The compound is sodium chloride 
6 0
2 years ago
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