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grandymaker [24]
3 years ago
9

How do you determine the possible quantum numbers for an atom?

Chemistry
1 answer:
mars1129 [50]3 years ago
4 0

The quantum numbers can be used to describe a specific electron in an atom of that element. There are four quantum numbers:

<span><span>n, the principal quantum number, which describes the shell of an electron;</span><span>l, the Azimuthal quantum number, which describes the subshell of an electron;</span><span><span>ml</span>, the magnetic quantum number, which describes/specifies the orbital an electron is in; and</span><span><span>ms</span>, the spin quantum number, which describes the spin of the electron.</span></span>

For example, if I was told that I had quantum numbers for a valence shell electron in the ground state for nitrogen were <span>n=2,l=1,<span>ml</span>=−1</span> and <span><span>ms</span>=+<span>12</span></span> then:

<span><span>The <span>n=2</span> tells me that we are describing a shell 2 electron.</span>the <span>l=1</span> describes the subshell as p. 
I now know we are talking about a shell 2, p subshell energy level for the electron.The <span><span>ml</span>=−1</span> would indicate the specific orbital in the p-subshell (there are three possible p-orbitals in this p-subshell with <span>ml</span> values = -1, 0, +1)We have specified the first 2p-subshell orbital with the <span>ml</span> value = -1. The spin quantum number of +1/2 indicates one of two possible spin quantum numbers (+1/2 and -1/2) for the two electrons that can fill this specific orbital in this specific subshell and shell.</span>
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1N2 + 3H2 --&gt;
Hunter-Best [27]

Answer:

28.23 g NH₃

Explanation:

The balanced chemical equation is:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Thus, 1 mol of N₂ reacts with 2 moles of H₂ to produce 2 moles of NH₃. We convert the moles to mass (in grams) by using the molecular weight (MW) of each compound:

MW(N₂) = 2 x 14 g/mol = 28 g/mol

mass N₂= 1 mol x 28 g/mol = 28 g

MW(H₂) = 2 x 1 g/mol = 2 g/mol

mass H₂ = 3 mol x 2 g/mol = 6 g

MW(NH₃) = 14 g/mol + (3 x 1 g/mol) = 17 g/mol

mass NH₃= 2 moles x 17 g/mol = 34 g

Now, we have to figure out which is the limiting reactant. For this, we know that the stoichiometric ratio is 28 g N₂/6 g H₂. If we have 36.85 g of H₂, we need the following mass of N₂:

36.85 g H₂ x 28 g N₂/6 g H₂ = 171.97 g N₂

We have 23.15 g N₂ and we need 171.97 g. So, we have lesser N₂ than we need. Thus, the limiting reactant is N₂.

Now, we calculate the product (NH₃) by using the stoichiometric ratio 34 g NH₃/28 g N₂, with the mass of N₂ we have:

23.25 g N₂ x 34 g NH₃/28 g N₂ = 28.23 g NH₃

Therefore, the maximum amount of NH₃ that can be produced is 28.23 grams.

5 0
3 years ago
The exact position of the electrons of an atom cannot be determined because they are in constant ___
PSYCHO15rus [73]
Movement
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3 0
3 years ago
At what temperature does a gas at 1.00 atm and 20 degree Celsius have a pressure of 4.00 atm.
vfiekz [6]

Answer:

P1 =4 atm

T1= 20°C

P2=1 atm

T2=?

According to Gay-Lussac's Law or Third Gas Law,

P1T2=P2T1

4×T2=1×20

T2= 20/4

T2= 5°C

Answer At 5°C temperature does a gas at 1.00 atm !

7 0
3 years ago
Give the clarification of heat and temperature on the basis of molecular motion?
sdas [7]

Explanation:

Heat is a form of thermal energy.

Heat is the sum of all the energy of the molecular motion in an object.

Temperature measures the average heat possessed by each molecule in a given substance.

 Molecules at a higher temperature possess more kinetic energy and they will move faster. This kinetic energy form is the heat variant of thermal energy.

Temperature is the measure of this heat energy of molecules.

8 0
3 years ago
determine the average volume from the following volume reading: 3.00ml, 2.0ml, 2.987 x 10^-3 l, and 3.4856 ml
lesya [120]

Answer:

The average of given values is 2.1221 ml

Explanation:

Given data:

Given measurements = 3.00 ml , 2.0 ml, 2.987 × 10⁻³ml , 3.4856 ml

Average value of given measurements = ?

Solution:

Formula:

Average value = sum of all measurement  / total number of measurements

2.987 × 10⁻³ml = 0.002987 ml

Now we will put the  values.

Average value = 3.00 ml + 2.0 ml + 0.002987 ml+ 3.4856 ml / 4

Average value = 8.488587 ml / 4

Average value =  2.1221 ml

The average of given values is 2.1221 ml

8 0
3 years ago
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