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grandymaker [24]
3 years ago
9

How do you determine the possible quantum numbers for an atom?

Chemistry
1 answer:
mars1129 [50]3 years ago
4 0

The quantum numbers can be used to describe a specific electron in an atom of that element. There are four quantum numbers:

<span><span>n, the principal quantum number, which describes the shell of an electron;</span><span>l, the Azimuthal quantum number, which describes the subshell of an electron;</span><span><span>ml</span>, the magnetic quantum number, which describes/specifies the orbital an electron is in; and</span><span><span>ms</span>, the spin quantum number, which describes the spin of the electron.</span></span>

For example, if I was told that I had quantum numbers for a valence shell electron in the ground state for nitrogen were <span>n=2,l=1,<span>ml</span>=−1</span> and <span><span>ms</span>=+<span>12</span></span> then:

<span><span>The <span>n=2</span> tells me that we are describing a shell 2 electron.</span>the <span>l=1</span> describes the subshell as p. 
I now know we are talking about a shell 2, p subshell energy level for the electron.The <span><span>ml</span>=−1</span> would indicate the specific orbital in the p-subshell (there are three possible p-orbitals in this p-subshell with <span>ml</span> values = -1, 0, +1)We have specified the first 2p-subshell orbital with the <span>ml</span> value = -1. The spin quantum number of +1/2 indicates one of two possible spin quantum numbers (+1/2 and -1/2) for the two electrons that can fill this specific orbital in this specific subshell and shell.</span>
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Answer:

B. 2 Na(s) + O₂(g) → Na₂O₂(s); ΔG∘f=−451.0 kJ/mol

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The spontaneity of a reaction  is given by the value of the standard Gibbs free energy of the reaction (ΔG°rxn). The more negative is the ΔG°rxn, the more spontaneous is a reaction.

The ΔG°rxn can be calculated using the following expression:

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By definition, the standard Gibbs free energy of formation of simple substances in their most stable state is zero. That is why, in the reaction of formation of a compound ΔG°rxn = ΔG°f(product).

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<em>     A. N₂(g) + H₂(g) → N₂H₄(g); ΔG°f=159.3 kJ/mol. </em>

<em>     </em>Not feasible. ΔG°rxn = ΔG°f(product) > 0.

    <em>B. 2 Na(s) + O₂(g) → Na₂O₂(s); ΔG°f=−451.0 kJ/mol</em>

    Feasible. ΔG°rxn = ΔG°f(product) < 0.

    <em>C. 2 C(s) + 2 H₂(g) → C₂H₄(g); ΔG°f=68.20 kJ/mol</em>

    Not feasible. ΔG°rxn = ΔG°f(product) > 0.

    <em>D. 2 SO(g) + O₂(g) → 2 SO₂(g); ΔG°f=−600.4 kJ/mol</em>

    Feasible. ΔG°rxn = ΔG°f(product) < 0.

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Now, isotope of magnesium of proton with 14 neutrons is Mg-16 .

Therefore, name of element is Mg-16 .

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