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grandymaker [24]
3 years ago
9

How do you determine the possible quantum numbers for an atom?

Chemistry
1 answer:
mars1129 [50]3 years ago
4 0

The quantum numbers can be used to describe a specific electron in an atom of that element. There are four quantum numbers:

<span><span>n, the principal quantum number, which describes the shell of an electron;</span><span>l, the Azimuthal quantum number, which describes the subshell of an electron;</span><span><span>ml</span>, the magnetic quantum number, which describes/specifies the orbital an electron is in; and</span><span><span>ms</span>, the spin quantum number, which describes the spin of the electron.</span></span>

For example, if I was told that I had quantum numbers for a valence shell electron in the ground state for nitrogen were <span>n=2,l=1,<span>ml</span>=−1</span> and <span><span>ms</span>=+<span>12</span></span> then:

<span><span>The <span>n=2</span> tells me that we are describing a shell 2 electron.</span>the <span>l=1</span> describes the subshell as p. 
I now know we are talking about a shell 2, p subshell energy level for the electron.The <span><span>ml</span>=−1</span> would indicate the specific orbital in the p-subshell (there are three possible p-orbitals in this p-subshell with <span>ml</span> values = -1, 0, +1)We have specified the first 2p-subshell orbital with the <span>ml</span> value = -1. The spin quantum number of +1/2 indicates one of two possible spin quantum numbers (+1/2 and -1/2) for the two electrons that can fill this specific orbital in this specific subshell and shell.</span>
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A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S
slamgirl [31]

The molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.

<h3>How to calculate molarity?</h3>

The molarity of a solution can be calculated using the following formula:

Molarity = no of moles/volume

According to this question, a solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water.

no.of moles of CuSO4 = 35g ÷ 159.6g/mol

no. of moles of CuSO4 = 0.22 moles

Therefore; molarity of CuSO4 solution is calculated as follows:

M = 0.22 ÷ 0.25

M = 0.88M

Therefore, the molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.

Learn more about molarity at: brainly.com/question/12127540

6 0
2 years ago
How many moles are in 13.1 grams of aluminum
Andrej [43]

Answer:

2 significant figure is 13.1 aluminium

5 0
3 years ago
what gas was given off when hydrogen peroxide is broken down? recall that the formula for hydrogen peroxide is h2o2?
Anna35 [415]
When hydrogen peroxide is broken down the gas released or given off is Oxygen. 
5 0
3 years ago
Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?
Mariulka [41]
  • Volume=V=3L
  • Pressure=P=814mmHg
  • Temp=T=25°C

So

No of moles=n

\\ \rm\rightarrowtail PV=nRT

\\ \rm\rightarrowtail n=\dfrac{PV}{RT}

\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}

\\ \rm\rightarrowtail n=2442/25R

\\ \rm\rightarrowtail n=97.7Rmol

5 0
2 years ago
For the following reaction in aqueous solution, identify all those species that will be spectator ions. Select all that apply.
uranmaximum [27]

The reaction is incorrect. The correct reaction is: Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃. The options are:

A. Hg₂SO₄

B. Na₂SO₄

C. Na⁺

D. NO₃⁻

E. SO₄⁻²

F. Hg₂(NO₃)₂

G. NaNO₃

H. Hg⁺²

Answer:

C, D, E, H

Explanation:

The ions are formed after dissociation of the compound in the solution. When they're negatively charged, they're called anions, when they're negatively charged, they're called cations. If the ion is presented on both sides of the reaction, it is called a spectator ion.

Thus, the reaction given:

Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃

So, let's do the dissociation.

Na₂SO₄ is formed by the ions Na⁺ and SO₄⁻²;

Hg(NO₃)₂ is formed by the ions Hg⁺² and NO₃⁻;

HgSO₄ is formed by the ions Hg⁺² and SO₄⁻²;

NaNO₃ is formed by the ions Na⁺ and NO₃⁻.

Thus, the spectator ions are Na⁺, SO₄⁻², Hg⁺², and NO₃⁻.

7 0
3 years ago
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