Question

What are the slope, m, y-intercept, (0,b), of the line described by the equation 3x + 6y= 12?

Answer 1

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

We have $3x+6y=12$.

Transform to the slope-intercept form.

$3x+6y=12$      subtract 3x from both sides

$6y=-3x+12$      divide both sides by 6

$y = -\dfrac{1}{2}x+2$

Answer:

$slope\ m=-\dfrac{1}{2}\\\\y-intercept:(0,\ 2)$