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vagabundo [1.1K]
3 years ago
11

Consider a metal single crystal oriented such that the normal to the slip plane and slip direction are at angles of 60° and 35°,

respectively, with the tensile axis. If the critical resolved shear stress is 8 MPa, will the applied stress of 12 MPa cause the single crystal to yield? If not, what stress will be necessary?
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

19.5324 MPa

Explanation:

Information provided

Angle between the normal to the slip plane with tensile axis, \alpha=60^{o}


Angle by slip direction with tensile axis, \beta=35^{o}

Critical resolved shear stress, \tau_{c}=8 MPa

Applied stress \sigma=12 MPa

Shear stress at slip plane

\tau=\sigma cos\alpha cos\beta

\tau=12cos60^{o}cos35^{o}=4.915 MPa

\tau hence crystal won’t yield

Applied stress, \sigma for crystal to yield is given by

\sigma=\frac {\tau_{c}}{cos\alpha cos\beta}

\sigma=\frac {8}{cos60cos35}=19.53239342 MPa

\sigma=19.5324 MPa


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