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KATRIN_1 [288]
4 years ago
12

Do roses have prokaryotic cells

Physics
1 answer:
o-na [289]4 years ago
3 0

No they don't. All plants are Eukaryotic/Eukaryotes.

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Goo.gle meet??<br><br> https://meet.go ogle.com/qzz-pxqd-gaj
Elenna [48]

Answer:

ok............I'll try ............

5 0
3 years ago
The atomic radius of metal X is 1.20 × 102 picometers (pm) and a crystal of metal X has a unit cell that is face-centered cubic.
dmitriy555 [2]
The density of the metal can be determined through the formula [n*MW]/ Na*[a^3] . substituting, we get, 

<span>d = [n*MW]/ Na*[a^3] 
</span><span>d = [4 atoms*42.3 g/mol]/ [6.022 x 1023atoms/mol* (sqrt 8 *1.20x10-10)^3] 
</span>d = 0.719 g/cm3
4 0
4 years ago
What type of weather does Los Angeles, California have?
storchak [24]

Answer:

Explanation:

Hot and breezy weathe

3 0
3 years ago
Read 2 more answers
Q. No. 9 A body falls freely from the top of a tower and during the last second of its fall, it falls through 25m. Find the heig
HACTEHA [7]

Answer:

45.6m

Explanation:

The equation for the position y of an object in free fall is:

y=-\frac{1}{2} gt^2+v_0t+y_0

With the given values in the question the equation has one unknown v₀:

v_0=\frac{y-y_0}{t}+\frac{1}{2}gt

Solving for t=1:

1) v_0=y-y_0+\frac{g}{2}

To find the hight of the tower you can use the concept of energy conservation:

The energy of the body 1 sec before it hits the ground:

2) E=\frac{1}{2}m{v_0}^2+mgy_0

If h is the height of the tower, the energy on top of the tower:

3) E=mgh

Combining equation 2 and 3 and solving for h:

4) h=\frac{{v_0}^2}{2g}+y_0

Combining equation 1 and 4:

h=\frac{{(y-y_0+\frac{g}{2}})^2}{2g}+y_0

4 0
3 years ago
A runner of mass 60.0kg runs around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its cent
Elenna [48]

Answer:

See explanation

Explanation:

In this exercise, we need to use the law of conservation of angular momentum which is:

I1*W1 + I2*W2 = (I1 + I2)*W2'

Where:

I: moment of innertia.

W: angular velocity

Now let's call 1 the runner and 2, the turntable. the system would be W2'.

The angular speed of the runner, we can calculate that with the following expression:

W = V/r

so:

W1 = 2.5 / 3.6 = 0.694 rad/s

The innertia is calculated with the expression:

I = m*r²

I = 60 * 3.6 = 216 kg.m²

I2 and W2 are provided in the exercise, so, replacing all the data in the conservation of angular momentum, let's solve for W2'

(216*0.694) + (-0.190*81) = (81 + 216)W2'

134.514 = 297W2'

W2' = 134.514 / 297

W2' = 0.453 rad/s

5 0
4 years ago
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