Describe how varying the incline plane angle Affects the force
1 answer:
Answer: the force increases as the angle increases
Explanation:
If we assume the incline plane is frictionless, the only force acting on an object on the incline plane is the force of gravity:
where m is the mass and g the acceleration due to gravity.
However, the actual force that makes the object sliding down along the incline is not the gravity itself, but the component of the force of gravity parallel to the surface of the incline, which is given by
where is the angle of the incline.
Therefore, we see that as the angle of the incline increases, the force on the object increases.
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Answer:
The grating spacing of the beetle is
Explanation:
The concept to solve this problem is relate to interference effect given in the Young's Slits. Here was demonstrated that the length of the side labelled \lambda is known as the path difference. The equation is given by,
Where,
= wavelenght of light
N = a positive integer: 1,2,3...
= Angle from the center of the wall to the dark spot
d= width of the slit
Replacing our values we have that for n=1,
Therefore the grating spacing of the beetle is
Answer:
Before the plank will tip cat will walk 1.652 m
Explanation:
Mass of the cat along with plank
Center of mass of the plank
Mass of cat
We have to find how far right of sawhorse B.
Plank will tip when weight of the cat about B is greater than the torque by the weight of the plank.
Balancing the the torque
Answer:
Explanation:
Height of building
H = 6m
Horizontal speed of first balloon
U1x = 2m/s
Second ballot is thrown straight downward at a speed of
U2y = 2m/s
Time each gallon hits the ground
Balloon 1.
Using equation of free fall
H = Uoy•t + ½gt²
Uox = 0 since the body does not have vertical component of velocity
6 = ½ × 9.8t²
6 = 4.9t²
t² = 6 / 4.9
t² = 1.224
t = √1.224
t = 1.11 seconds
For second balloon
H = Uoy•t + ½gt²
6 = 2t + ½ × 9.8t²
6 = 2t + 4.9t²
4.9t² + 2t —6 = 0
Using formula method to solve the quadratic equation
Check attachment
From the solution we see that,
t = 0.9211 and t = -1.329
We will discard the negative value of time since time can't be negative here
So the second balloon get to the ground after t ≈ 0.92 seconds
Conclusion
The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.
