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DanielleElmas [232]
3 years ago
9

Find the volume of the cylinder. Round your answer to the nearest tenth.

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

803.8 cubic centimeters (to the nearest tenth)

Step-by-step explanation:

Volume of a cylinder, V = πr²h

π = 3.14

From the question,

r = radius = diameter/2 = 8cm/2 = 4cm

h = height of the cylinder = 16cm

We substitute these values into the formula

V = πr²h

V = 3.14 X 4²cm² X 16cm

V = 803.8cm³

Therefore, the volume of the cylinder is 803.8 cubic centimeters to the nearest tenth

GrogVix [38]3 years ago
7 0

We know diameter d=8 and height h=16.

First find the radius of the bottom of the cylinder,

r=\dfrac{d}{2}=\dfrac{8}{2}=4.

Then find the area of the bottom of cylinder,

A=\pi r^2=16\pi.

Then to find volume just multiply the height with the area of the bottom of the cylinder,

V=Ah=16\cdot16\pi=16^2\pi\approx804.247\mathrm{cm^3}.

Hope this helps.

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Which of the following fractions is equal to a repeating decimal
kiruha [24]

Answer: There are no fractions listed, so I can't help you. 1/3 is a repeating though, if that helps anything. Otherwise, you could use a calculator and just find the decimal of the fraction.

4 0
3 years ago
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Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
If you thought the last one was easy do this >:)
avanturin [10]
I have no idea what the answer is to this question
7 0
3 years ago
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Plot (25/3) and (42/3) on the number line.
ss7ja [257]

Answer:

Refer to the Attachment

Step-by-step explanation:

Rewriting the fractions in decimal and whole number, we have the following:

\frac{25}{3} = 8\frac{1}{3} = 8.3

\frac{42}{3} = 14

Thus, 42/3 is on 14 and 25/3 is on 8 and then add 1/3 from 8 going to 9.

Therefore, the points must be plotted as follows:

The blue point indicates the 42/3 while the red point indicates the 25/3.

8 0
3 years ago
"use the graph to determine the limit if it exists" limit x -> 3 I provided graph below
bekas [8.4K]

Answer:

im not sure but probably 18

Step-by-step explanation:

5 0
3 years ago
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