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kherson [118]
3 years ago
14

the length of a rectangle is the width minus 3 units the area of the rectangle is 18 units what is the width in units of the rec

tangle ​

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer:

Step-by-step explanation:

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34 is larger than 3, so 34.653
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In a certain arithmetic sequence, if -4 is the first term and 10 is the third term, which term is 157?
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a₁₅₇ = 1,088

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Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
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Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

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