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bija089 [108]
3 years ago
15

Mrs. Stevens wants to have $18,000 in the bank in 3 years. If she deposits $9500 today at 4% compounded quarterly for 3 years, h

ow much additional money will she need to add after three years to her investment to make her balance $18000?
a.
$8356.79
b.
$0
c.
$7295.16
d.
$10,704.84
Mathematics
2 answers:
serg [7]3 years ago
7 0
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad 
\begin{cases}
A=\textit{current amount}\\
P=\textit{original amount deposited}\to &\$9500\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, 4 quarters a year}
\end{array}\to &4\\

t=years\to &3
\end{cases}

so.. if she deposits a principal of 9,500 today, compounding quarterly for 3 years, she'll have A amount

how much additional amount?  well, 18,000 - A
Andrews [41]3 years ago
5 0
A=p(1+i/m)^mn
A=9,500×(1+0.04÷4)^(4×3)
A=10,704.84
The balance she needs

18,000−10,704.84
=7,295.16
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Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
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Now substitute 50 - S for A in the second equation.

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6 0
3 years ago
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6 0
3 years ago
Read 2 more answers
Aaron has $4,500 saved to pay for an ATV that costs $7,500.
Komok [63]

Answer:

i think its 0.9994225

Step-by-step explanation:

just subtract the 8.75136.24 bye 7.75193. and there you go.

6 0
3 years ago
A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac
sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant =  0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g

     

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0
3 years ago
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