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notsponge [240]
4 years ago
12

Ray created the list of factors for 48 below.

Mathematics
2 answers:
bulgar [2K]4 years ago
6 0

Answer:

the correct answer is 7

Step-by-step explanation:

i got 48 wrong on my test

noname [10]4 years ago
4 0
48 Is the answer that should be removed !
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How much to the nearest dollar should you deposit in a savings account at 2.5% annual simple interest in order to have a balance
Aneli [31]

Answer:

The amount we have to deposit in a savings account x = $ 17777.78

Step-by-step explanation:

Amount = $ 20000

R = 2.5 %

Time = 5 years

Take principal amount = x

Simple interest earned in five years

S.I. = \frac{P R T}{100}

S.I. = \frac{P (2.5)(5)}{100}

S.I. = \frac{x}{8}   ------- (1)

We know hat total amount is given by

Total amount = principal amount + simple interest

A = x + S.I.

A = x + \frac{x}{8}

A = \frac{9x}{8}

Given that the total amount after 5 years is = $ 20000

\frac{9x}{8} = 20000

x = $ 17777.78

This is the amount we have to deposit in a savings account.

6 0
3 years ago
The equipment operates 5 days a week for 12 hours each day according to last weeks production numbers shown in the table how man
Pani-rosa [81]

Answer:

cawnser is 60

Step-by-step explanation:

because 5 times 12 is 60 hours

8 0
3 years ago
What is an end point of a ray
Slav-nsk [51]

Answer:

The end point of a ray is A

Step-by-step explanation:

Hope this Helps

5 0
3 years ago
13. Mark has a board that is 12 feet long. He
horrorfan [7]

Answer:

1.5 feet

Step-by-step explanation:

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6 0
3 years ago
Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

4 0
3 years ago
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