Answer:
141.4 sq cm
Step-by-step explanation:
to find the area of the outer circle with a smaller circle inscribed within, you find the area of each and subtract the smaller area from the larger
the radius of the smaller circle is 2
we have to find the radius of the larger circle so we use what we know about its circumference:
C = 2πr
43.96 = 2πr
21.98 = πr
21.98 / π = r
r ≈ 7 cm
now use r = 7 to find area of larger circle:
A = πr²
A = π49
Area of smaller circle: 4π
Area of larger circle without including inner section is 49π - 4π = 45π
45π ≈ 141.4 sq cm
Answer:
There is a typo near the equal sign.
There can be two different answers if we think that = sign as + or -.
First way: Making = as +
=> 10 - [14 + (3+4) x 2] +3
=> 10 - [14 + 7 x 2] + 3
=> 10 - [14 + 14] + 3
=> 10 - 28 + 3
=> 10 + 3 - 28
=> 13 - 28
=> -15
=> So, -15 is the answer if we consider "=" sign as "+" sign.
Second way: Making = as -
=> 10 - [14 - (3+4) x 2] + 3
=> 10 - [14 - 7 x 2] + 3
=> 10 - [14 - 14] + 3
=> 10 - 0 + 3
=> 10 + 3
=> 13
=> So, 13 is the answer if we consider "=" sign as "-" sign.
Answer:
x = 7
Step-by-step explanation:
4 + 5(x + 2) = 7x
4 + 5x + 10 = 7x
5x - 7x = - 4 - 10
- 2x = - 14
- x = - 14/2
- x = - 7
x = 7
Answer:
Step-by-step explanation:
To create an augmented matrix, we need to transfer the coefficients of each system of equations into its respective place in the matrix. The first row will be the coefficients of the first equation and so on. The number to the right of the equals sign is the last column of the augmented matrix.
![\left[\begin{array}{ccc|c}1&-1&8&8\\3&-9&1&-1\\8&1&0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%26-1%268%268%5C%5C3%26-9%261%26-1%5C%5C8%261%260%260%5Cend%7Barray%7D%5Cright%5D)
Answer:
Step-by-step explanation:
15 minutes
