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choli [55]
4 years ago
6

How many ounces of trail mix are in a bag that weighs 0.681 kilograms? Input only numeric values. (1 pound = 0.454 kg and 1 poun

d = 16 ounces)
Mathematics
2 answers:
Lesechka [4]4 years ago
8 0

Answer:

1.501

Step-by-step explanation:

vivado [14]4 years ago
7 0

Answer:

24 ounces

Step-by-step explanation:

the math is.  

.681÷ .454= 1.5 which is in pounds than you take 16÷2= 8 take that 8 add it to the 16 giving you 24 ounces

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M = 22 and p = 24<br> (p+ m) : 4
Blababa [14]

Answer:

p+m=46

46:4=11.5

Step-by-step explanation:

good luck

4 0
3 years ago
there 176 slices of bread in 8 loaves. if there are the same number of slices in each loaf, how many slices of bread are in 5 lo
ahrayia [7]
There is 110 slices of bread total in 5 loaves.
170/8=22
22*5=110
5 0
4 years ago
Read 2 more answers
HELP NOWWWWW PLEASEEE
Amiraneli [1.4K]

Answer:

46N

Step-by-step explanation:

surface area of box =5*1+5*3+5*1+7*3=46sqm

4 0
2 years ago
Which numbers are necessary to solve this problem? Franklin brought 4 jump ropes to the park. Each jump rope can be used by 3 pe
Luda [366]

Answer:

  D. 4 jump ropes, 3 people, 15 friends

Step-by-step explanation:

In order to answer the question how many friends could play, you need to be able to determine the smaller of ...

  • (number of ropes) × (friends per rope)
  • number of friends

You can find the first of these numbers using the values of answer A, but if the number of Franklin's friends is smaller than 12, then you need to know that in order to properly answer the question. Hence, we believe you need to know ...

  • the number of jump ropes
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4 0
4 years ago
A certain article reported the following observations, listed in increasing order, on drill lifetime (number of holes that a dri
aleksklad [387]

Answer:

Sample mean =119.42

Median = 92

25% trimmed mean = 102.42

10% trimmed mean = 95.69

Step-by-step explanation:

Data in increasing order :

12 13 20 23 31 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249 262 289 323 388 513

Total no. of observations = 50

Sample mean = \frac{\text{Sum of all observations}}{\text{Total number of observations}}

= \frac{5971}{50} = 119.42

Median: Since we have even number of observation

Median = \frac{1}{2}({25\text{th term} + 26\text{th term}) = \frac{91+93}{2} = 92

10% Trimmed Mean: We remove 5 values from each side

Trimmed set = 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{4097}{40} = 102.42

25% Trimmed Mean: We remove 12 values from each side.

Trimmed set =  66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{2488}{26} = 95.69

6 0
3 years ago
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