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Gnom [1K]
3 years ago
15

Can someone help me with this geometry question?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

(-1,4.5)

Step-by-step explanation:

You would have to use the formula for midpoint. 5+-3/2= -1

3+6/2= 4.5  which would be -1 for x and 4.5 for y.

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What is the answers to the question: Which rational expression is undefined when x = 0?
Rom4ik [11]

Answer:

option D

\frac{4x-8}{-2x^2}

Step-by-step explanation:

An expression is undefined when you get division by zero or in simple words when denominator is zero.

Now we will solve each expression one be one by plugging value of x = 0

<h3>1)</h3><h3>\frac{5x^2-4}{3x-3}</h3>

\frac{5(0)-4)}{3(0)-3}

-4/-3 = 4/3

<h3>2)</h3><h3>\frac{6x^2}{9x-3}</h3>

\frac{6(0)}{9(0)-3}

0/-3 = 0

<h3>3)</h3>

\frac{8x+6}{-x^2+1}

\frac{8(0)+6}{-0+1}

6/1

6

<h3>4)</h3>

\frac{4x-8}{-2x^2}

\frac{4(0)-8}{-2(0)}

<h3>-8/0</h3><h3>undefined</h3>

8 0
3 years ago
Read 2 more answers
Plzz help please.......​
kap26 [50]

Answer:

6.71

You use pythagoras so you do:

6² + 3² = 45

square root 45 =6.71

6 0
3 years ago
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answer 143.00 Step-by-step explanation:

5 0
3 years ago
In pensacola in june, high tide was at noon. the water level at high tide was 12 feet and 2 feet at low tide. assuming the next
castortr0y [4]

An equation for water level in june for pensacola as a function of time (t) is f(t) = 5 cos pi/6 t + 7.

Which equation of cos show period amplitude ?

The equation given below show aplitude and period

y = A cos bx + c

where A = amplitude,

b = 2 pi/Period,

Period = 12 hrs,

c = midline,

x = t and y = f(t)

We have to find the amplitude

<h3>What is the formula for the amplitude?</h3>

A = 1/2 (Xmax - Xmin)

12 - 2 / 2 = 10/2 = 5

b = 2 pi / 12 = pi/6

c = 1/2 (Xmax + Xmin)

12+2/2 = 7

Therefore, the an equation for water level in june for pensacola as a function of time (t)

f(t) = 5 cos pi/6 t + 7

To learn more about the function of time visit:

brainly.com/question/24872445

3 0
2 years ago
A park is in the shape of a rectangle. The park is 5/8 mile long and 2/3 mile wide. What is the area of the park?
Elenna [48]
To find the area of a rectangle, you times the length and width together. 
So in this case, 
5/8 x 2/3 = 10/24. 
This can be simplified to 5/12
7 0
3 years ago
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