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Gnom [1K]
3 years ago
15

Can someone help me with this geometry question?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

(-1,4.5)

Step-by-step explanation:

You would have to use the formula for midpoint. 5+-3/2= -1

3+6/2= 4.5  which would be -1 for x and 4.5 for y.

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A researcher is interested in estimating the mean weight of a semi trailer truck to determine the potential load capacity. She t
Kaylis [27]

Answer: 95% confidence interval = 20,000 ± 2.12\times\frac{1500}{\sqrt{17} }

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

Step-by-step explanation:

Given :

Sample size(n) = 17

Sample mean = 20000

Sample standard deviation = 1,500

5% confidence

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Degree of freedom (d_{f}) = n-1 = 16

∵ Critical value at ( 0.025 , 16 ) = 2.12

∴ 95% confidence interval = mean ± Z_{c}\times\frac{\sigma}{\sqrt{n} }

Critical value  at 95% confidence interval = 20,000 ± 2.12\times\frac{1500}{\sqrt{17} }

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

3 0
3 years ago
−2/3(3x−4)+3x=5/6 whoever gets right gets brainlyest
REY [17]

−2/3(3x−4)+3x=5/6

= -11/6

7 0
3 years ago
Read 2 more answers
Suppose that x has a binomial distribution with n = 201 and p = 0.45. (Round np and n(1-p) answers to 2 decimal places. Round yo
ycow [4]

Answer:

a) It can be used because np and n(1-p) are both greater than 5.

Step-by-step explanation:

Binomial distribution and approximation to the normal:

The binomial distribution has two parameters:

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p, which is the probability of a success on a single trial.

If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.

In this question:

n = 201, p = 0.45

So, lets verify the conditions:

np = 201*0.45 = 90.45 > 5

n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5

Since both np and n(1-p) are greater than 5, the approximation can be used.

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3 years ago
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3 years ago
How to measure and find the circumcenter of a triangle
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Circumcenter Calculator

Circumcenter of triangle can be defined as the point where the three perpendicular bisectors of the sides of the triangle meet. The distance of vertices of triangle is equal to circumcenter.

It is the single point where the perpendicular bisectors of the three sides of the triangles meet .
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