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77julia77 [94]
3 years ago
9

Find the width of a rectangle is the perimeter is 56 cm and the length is 15 cm.

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

13cm

Step-by-step explanation:

P=2l+2w

56=2(15)+2w

56=30+2w

26=2w

w=13

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A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6
ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

<u>Now, According to question</u>

The population of bacteria after 6 days = initial population × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, f = i × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, f = 1000 × (1+\dfrac{\textrm 15}{100})^{\textrm 6}

Or, f = 1000 × (1.15)^{6}

Or, f = 1000 × 2.31306

∴  f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06  Answer

3 0
3 years ago
Determine whether each of the binary relation R defined on the given sets A is reflexive, symmetric, antisymmetric, or transitiv
ki77a [65]

Answer:

In explanation

Please let me know if something doesn't make sense.

Step-by-step explanation:

a)

*This relation is not reflexive.

0 is an integer and (0,0) is not in the relation because 0(0)>0 is not true.

*This relation is symmetric because if a(b)>0 then b(a)>0 since multiplication is commutative.

*This relation is transitive.

Assume a(b)>0 and b(c)>0.

Note: This means not a,b, or c can be zero.

Therefore we have abbc>0.

Since b^2 is positive then ac is positive.

Since a(c)>0, then (a,c) is in R provided (a,b) and (b,c) is in R.

*The relation is not antisymmretric.

(3,2) and (2,3) are in R but 3 doesn't equal 2.

b)

*This relation is reflective.

Since a^2=a^2 for any a, then (a,a) is in R.

*The relation is symmetric.

If a^2=b^2, then b^2=a^2.

*The relation is transitive.

If a^2=b^2 and b^2=c^2, then a^2=c^2.

*The relation is not antisymmretric.

(1,-1) and (-1,1) is in the relation but-1 doesn't equal 1.

c)

*The relation is reflexive.

a/a=1 for any a in the naturals.

*The relation is not symmetric.

Wile 4/2 is an integer, 2/4 is not.

*The relation is transitive.

If a/b=z and b/c=y where z and y are integers, then a=bz and b=cy.

This means a=cyz. This implies a/c=yz.

Since the product of integers is an integer, then (a,c) is in the relation provided (a,b) and (b,c) are in the relation.

*The relation is antisymmretric.

Assume (a,b) is an R. (Note: a,b are natural numbers.) This means a/b is an integer. This also means a is either greater than or equal to b. If b is less than a, then (b,a) is not in R. If a=b, then (b,a) is in R. (Note: b/a=1 since b=a)

6 0
3 years ago
Symplify 5+2(x-5) <br><br> These letter and words are just to add stuff please
Nataliya [291]

I think it should be 7x-35

8 0
3 years ago
I need to solve this can anyone solve this?
xenn [34]

Answer:

d = 7

Step-by-step explanation:

7 times 5 = 35

or

35/5 = 7

4 0
3 years ago
Please help me!! I'll give brainliest btw
guajiro [1.7K]

Answer:

e. cannot be determined

Step-by-step explanation:

m = 1/2( x + x + 10) = 1/2(2x + 10) = x + 5

n = 1/2(x² + x + 10) =

m/n = (x+5)/(1/2(x² + x + 10))

Not enough information

6 0
3 years ago
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