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monitta
3 years ago
6

A moderately active 40-pound dog needs an average of 1,110 calories per day. Taryn's dog played extra hard at the dog park this

morning and will need to consume more than the average calories. Taryn's dog has already eaten 666 calories, and she feeds her dog 222 calories per meal.
222x + 666 > 1,110

How many more meals does Taryn need to feed her dog today?
pls help i gotta go somewhere and i gotta get this done thank you if u try
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0
Jey igd 102837 okay love you
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The table show four transactions and the resulting account balance in a bank account, except some numbers are missing. fill in t
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3 years ago
The value of an antique car is modeled by the function V(x)=107,000(1.009)^
drek231 [11]
To get a percent rate, let the value of the car based on two consecutive years. The variable x represents a year. You can set any two numbers of year as long as they are consecutive; say x = 0 and x = 1.

Use the calculator to get instantly the values of V(x).
For V(x = 0)
V(x = 0) = 107,000(1.009)^[2/3(0)] = 107,000

For V(x = 1)
V(x - 1) = 107,000(1.009)^[2/3(1)] = 107,641

Another way of getting the percentage between two values is called the "relative change."
(107,641 - 107,000) / 107,000 = 0.0060 = 0.60%
7 0
3 years ago
What is the range of the function represented by the graph?<br> {0,1,2,3} {1,2,3,4} 1
Minchanka [31]

Answer:

number 3

Step-by-step explanation:

6 0
3 years ago
Use a triple integral to find the volume of the tetrahedron T bounded by the planes x+2y+z=2, x=2y, x=0 and z=0
Tanzania [10]

Answer:

Volume of the Tetrahedron T =\frac{1}{3}

Step-by-step explanation:

As given, The tetrahedron T is bounded by the planes x + 2y + z = 2, x = 2y, x = 0, and z = 0

We have,

z = 0 and x + 2y + z = 2

⇒ z = 2 - x - 2y

∴ The limits of z are :

0 ≤ z ≤ 2 - x - 2y

Now, in the xy- plane , the equations becomes

x + 2y = 2 , x = 2y , x = 0 ( As in xy- plane , z = 0)

Firstly , we find the intersection between the lines x = 2y and x + 2y = 2

∴ we get

2y + 2y = 2

⇒4y = 2

⇒y = \frac{2}{4} = \frac{1}{2} = 0.5

⇒x = 2(\frac{1}{2}) = 1

So, the intersection point is ( 1, 0.5)

As we have x = 0 and x = 1

∴ The limits of x are :

0 ≤ x ≤ 1

Also,

x = 2y

⇒y = \frac{x}{2}

and x + 2y = 2

⇒2y = 2 - x

⇒y = 1 - \frac{x}{2}

∴ The limits of y are :

\frac{x}{2} ≤ y ≤ 1 - \frac{x}{2}

So, we get

Volume = \int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}\int\limits^{2-x-2y}_{z=0} {dz} \, dy  \, dx

             = \int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{[z]}\limits^{2-x-2y}_0 {} \,   \, dy  \, dx

             = \int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{(2-x-2y)} \,   \, dy  \, dx

             = \int\limits^1_0 {[2y-xy-y^{2} ]}\limits^{1-\frac{x}{2}} _{\frac{x}{2} } {} \, \, dx

             = \int\limits^1_0 {[2(1-\frac{x}{2} - \frac{x}{2})  -x(1-\frac{x}{2} - \frac{x}{2}) -(1-\frac{x}{2}) ^{2}  + (\frac{x}{2} )^{2} ] {} \, \, dx

             = \int\limits^1_0 {(1 - 2x + x^{2} )} \, \, dx

             = {(x - x^{2}  + \frac{x^{3}}{3}  )}\limits^1_0

             = 1 - 1² + \frac{1^{3} }{3} - 0 + 0 - 0

             = 1 - 1 + \frac{1 }{3} =  \frac{1}{3}

So, we get

Volume =\frac{1}{3}

7 0
3 years ago
Shelly has a roll of fabric and decides to make some scarves for her friend the roll contains 6 2/3 yards of fabric she needs 5/
ivann1987 [24]

Answer:

8

Step-by-step explanation:

Total length of the fabric is 6\dfrac{2}{3}=\dfrac{20}{3}\ \text{yards}

We need to find the number of scarves can she make if she needs 5/6 of a yard for each scarf.

Let she needs x scarves. So, ATQ

x\times \dfrac{5}{6}=\dfrac{20}{3}\\\\x=\dfrac{20}{3}\cdot\dfrac{6}{5}\\\\x=8

Hence, she can make 8 scarves.

8 0
3 years ago
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