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sattari [20]
3 years ago
15

Which represents the graph

Mathematics
1 answer:
frozen [14]3 years ago
6 0
<h3>Answer: Choice C.   y = -|x-1| + 3</h3>

=========================================

Work Shown:

General form of absolute value equations

y = a|x-h| + k

The 'a' determines if the V shape is upside down or not. If a > 0, then we have a V shape that isn't upside down. If a < 0, then the V shape is upside down as this diagram shows. In this case, a = -1.

The (h,k) is the vertex of the graph. For upside down V shaped graphs, the vertex is the highest point, which is (1, 3) in this case.

(h,k) = (1,3)

h = 1 and k = 3

So,

y = a|x-h|+k

y = -1|x-1| + 3

y = -|x-1| + 3

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Given:

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We have,

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(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

Therefore, the required radical form is \sqrt[5]{8y^3}\sqrt[10]{x^9}.

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3 years ago
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