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3 years ago

Select all of the choices that are equal to -5 - (-12) and

Mathematics

2 answers:

nexus9112 [7]3 years ago

5 0

Answer:

B,C,E.

Step-by-step explanation:

I did the quiz and got 100%

Lesechka [4]3 years ago

3 0

Answer:it’s 9

Step-by-step explanation:

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Match each circular flower bed on the left to its circumference and its area on the right. Some answer options on ti

user100 [1]

Answer:

Flower bed A has circumference = 31 feet, area = 79 feet²

Flower bed B has circumference = 38 feet, area = 113 feet²

Step-by-step explanation:

* Lets revise the rules of the circumference and the area of the circle

- The circumference of the circle = 2πr

- The Area of the circle = πr²

- r is the radius of the circle and it is half the diameter of the circle

# Flower bed A has a diameter 10 feet

∵ The radius = 1/2 the diameter

∴ The radius = 1/2 × 10 = 5 feet

∵ The circumference = 2πr

∴ The circumference = 2 × π × 5 = 31.42 ≅ 31 feet

∵ The area = πr²

∴ The area = π (5)² = 78.54 ≅ 79 feet²

* Flower bed A has circumference = 31 feet, area = 79 feet²

# Flower bed B has a radius 6 feet

∵ The circumference = 2πr

∴ The circumference = 2 × π × 6 = 37.70 ≅ 38 feet

∵ The area = πr²

∴ The area = π (6)² = 113.10 ≅ 113 feet²

* Flower bed B has circumference = 38 feet, area = 113 feet²

* These answers not in the choices

8 0

3 years ago

F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x

olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

$V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy$

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

$V=9\int\limits^2_0 {4y^{3}/3} \, dy$

After performing the elementary y integral we obtain the desired volume as below,

$V= 48 units^{3}$

4 0

3 years ago

Lim θ→0 cos(7θ) − 1/sin(5θ)

egoroff_w [7]

This was 4 days ago!!!!!!

6 0

3 years ago

Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2

valentina_108 [34]

Answer:

Solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

Step-by-step explanation:

We need to solve the equation $x^2+6x-8=0$ by completing the square method.

For completing the square method: we need to follow: $a^2+2ab+b^2=(a+b)^2$

We are given:

$x^2+6x-8=0$

Solving by completing the square

$x^2+2(x)(?)+(?)^2-8=0$

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

$x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17$

So, solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

7 0

3 years ago

Legs and hypotenuse

zaharov [31]

Answer:

Step-by-step explanation:

For a right triangle, the side that is opposite of the right angle is called the hypotenuse. This side will always be the longest side of the right triangle. The other two (shorter) sides are called legs.

3 0

3 years ago