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LenaWriter [7]
2 years ago
14

What part of students like lemonade

Mathematics
1 answer:
Sphinxa [80]2 years ago
7 0

Probably 23 not sure

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PLS HELP ME GUYS ITS MY LAST QUESTION IN GEOMETRY
aliina [53]

Answer:

Example = ( 12, 1 )

Step-by-step explanation:

There are many possible solutions to this equation, and all you would have to do to determine the ordered pair, is satisfy the following criteria -

x - 6y = 6,\\- 6y = - x + 6,\\y = 1 / 6x - 1

Take a look at a graph of the line y = 1 / 6x - 1. Any ordered pair that lies on this line is a solution to the equation. The " criteria " is that the ordered pair must lie on this line. Let me give you an example, ( 12, 1 ).

<u><em>Hope that helps!</em></u>

7 0
2 years ago
PLEASE HELP ME BY ANSWERING AT LEAST 2 QUESTIONS MY WORK IS DUE IN LESS THAN AN HOUR!
levacccp [35]

nononononon nonononononno

Step-by-step explanation:

nonononononomonjknonkkom

8 0
3 years ago
When a bactericide is added to a nutrient broth in which bacteria are​ growing, the bacteria population continues to grow for a​
baherus [9]

Answer:

a)  1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t​ is given by:

b(t) = 9^6 + 6^4t-6^3t^2

We differentiate the given function.

Thus, the growth rate is given by:

\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t

a) Growth rates at t = 0 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}

b) Growth rates at t = 3 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}

c) Growth rates at t = 6 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}

3 0
3 years ago
Let f(x) =3x-1 find f(-58) and f(24)
elena55 [62]


Sub -58 and 24 in the equation

F(-58) = 3(-58) - 1

F (-58) = -175

F(24) = 3 (24) - 1

F (24) = 71

4 0
3 years ago
Which type of correlation would you expect to see between the cost of roses and the number of roses sold?
morpeh [17]
B. negative correlation because as the price increases, the sales decrease
7 0
3 years ago
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