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MrRa [10]
4 years ago
5

While it is important to gain information on the prospect, it is relatively unimportant to gain any information on the prospect’

s organization prior to initiating sales dialogue.ANS:FPTS:1DIF:Difficulty: EasyREF:p. 124-125OBJ:LO: 5-5
Engineering
1 answer:
Tema [17]4 years ago
3 0

Answer:

<u>FALSE.</u>

Explanation:

This statement can be considered false, because it is important to know essential aspects of the prospect before starting the sales dialogue.

In addition to obtaining basic information about the client, it is relevant for the company to know the prospect's organization.

We can define the prospect as the one who, for the company, has the ideal customer profile, but who has not yet shown interest in consuming its products and services.

Therefore, knowing information about it, about its basic and complex characteristics will help the organization to develop sales and marketing strategies aimed at attracting the prospect.

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How to clean a snowblower carburetor without removing it.
Anarel [89]

Answer:

Spray carburetor cleaner on the inside of the bowl and wipe the liquid, dirt, and concentrated fuel off of it. Now take the main jet, spray the cleaner through it and wipe off the dirt. Then take a copper wire, scrub it through the tiny holes in the jet to complete the cleaning process.

Explanation:

8 0
3 years ago
Calculate the "exact" alkalinity of the water in Problem 3-2 if the pH is 9.43.
marin [14]

Answer:

A) approximate alkalinity = 123.361 mg/l

B) exact alkalinity = 124.708 mg/l

Explanation:

Given data :

A) determine approximate alkalinity first

Bicarbonate ion = 120 mg/l

carbonate ion = 15 mg/l

Approximate alkalinity = ( carbonate ion ) * 50/30  + ( bicarbonate ion ) * 50/61

                                   = 15 * (50/30) + 120*( 50/61 )  = 123.361 mg/l  as CaCO3

B) calculate the exact alkalinity of the water if the pH = 9.43

pH + pOH = 14

9.43 + pOH = 14. therefore pOH = 14 - 9.43 = 4.57

[OH^- ] = 10^-4.57  = 2.692*10^-5  moles/l

[ OH^- ]   = 2.692*10^-5  * 179/mole * 10^3 mg/g  = 0.458 mg/l

[ H^+ ] = 10^-9.43 * 1 * 10^3  = 3.7154 * 10^-7 mg/l

therefore the exact alkalinity can be calculated as

= ( approximate alkalinity ) + ( [ OH^- ] * 50/17 ) - ( [ H^+ ] * 50/1 )

= 123.361 + ( 0.458 * 50/17 ) - ( 3.7154 * 10^-7 * 50/1 )

= 124.708 mg/l

8 0
3 years ago
Read through the solution below. Then, answer the questions that follow.
nlexa [21]

Answer:

In the line marked *, the strategy that was used was renaming a fraction

The expression de-c fills in the orange box.

Explanation:

just did those questions 2020egen

8 0
4 years ago
Read 2 more answers
A weight-lifting athlete raises a mass of 160 kg through a vertical distance of 1.4 m. What force did
Over [174]

Answer:

1568N

2195.2J

Explanation:

Given parameters:

Mass of the weight = 160kg

Distance  = 1.4m

Unknown:

Force applied to lift the weight = ?

Energy expended  = ?

Solution:

The force applied in moving a body with a given mass through a distance is the weight;

     Force applied  = mg

Where m is the mass

           g is the acceleration due to gravity

i.  Applied force = 160 x 9.8  = 1568N

ii. The energy used to lift the weight is given as;

     Energy  = mgh

h is the vertical distance

     Energy  = 1568 x 1.4  = 2195.2J

8 0
3 years ago
A 3-oz serving of roasted, skinless chicken breast contains 140 Cal, 27 g of protein, 3 g of fat, 13 mg of calcium, and 64 mg of
Art [367]

Answer:

Explanation:

  • a) Given C [ cal pro fat calc sod]

              [140 27 3  13  64]

  • P = [cal pro fat calc sod]

     [180 4 11 24 662]

  • B = [cal pro fat calc sod]

      [50  5    1  82   20]

To find C+2P+3B = [140 27 3  13  64] + 2[180 4 11 24 662] + 3[50  5    1  82   20]

= [650  54  28  307  1448]

The entries represent skinless chicken breast , One-half cup of potato salad and One broccoli spear.

7 0
3 years ago
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