Answer:
winter viscosity grades
Explanation:
The “W”/winter viscosity grades describe the oil's viscosity under cold temperature engine starting conditions. There's a Low Temperature Cranking Viscosity which sets a viscosity requirement at various low temperatures to ensure that the oil isn't too thick so that the starter motor can't crank the engine over.
Answer:
(A) Maximum voltage will be equal to 333.194 volt
(B) Current will be leading by an angle 54.70
Explanation:
We have given maximum current in the circuit 
Inductance of the inductor 
Capacitance 
Frequency is given f = 44 Hz
Resistance R = 500 ohm
Inductive reactance will be 
Capacitive reactance will be equal to 
Impedance of the circuit will be 
So maximum voltage will be 
(B) Phase difference will be given as 
So current will be leading by an angle 54.70
The reason you dream about him is because you continuously think about him, maybe even before falling asleep.
Answer:
If the heat engine operates for one hour:
a) the fuel cost at Carnot efficiency for fuel 1 is $409.09 while fuel 2 is $421.88.
b) the fuel cost at 40% of Carnot efficiency for fuel 1 is $1022.73 while fuel 2 is $1054.68.
In both cases the total cost of using fuel 1 is minor, therefore it is recommended to use this fuel over fuel 2. The final observation is that fuel 1 is cheaper.
Explanation:
The Carnot efficiency is obtained as:

Where
is the atmospheric temperature and
is the maximum burn temperature.
For the case (B), the efficiency we will use is:

The work done by the engine can be calculated as:
where Hv is the heat value.
If the average net power of the engine is work over time, considering a net power of 2.5MW for 1 hour (3600s), we can calculate the mass of fuel used in each case.

If we want to calculate the total fuel cost, we only have to multiply the fuel mass with the cost per kilogram.
