The equation of the graph, in slope-intercept form, is: C. y = 2/3x + 6.
<h3>How to Write a Linear Equation in Slope-Intercept Form?</h3>
The linear equation of a graph in slope-intercept form is expressed as y = mx + b. Where the variable in the equation are as follows:
- b = y-intercept (this is the point on the y-axis where the line intercepts).
- m = slope (this is the rise/run along the line = change in y / change in x).
Considering the graph given, to write the linear equation it represents, find the slope (m) and the y-intercept (b) of the line.
Slope (m) = rise/run = 2 units/3 units
Slope (m) = 2/3.
The line intercepts the y-axis at y = 6, thus, the y-intercept (b) would be 6. b = 6.
Substitute m = 2/3 and b = 6 into the slope-intercept form equation, y = mx + b:
y = 2/3x + 6
Thus, the equation, in slope-intercept form, that represents the linear graph as shown in the image given is: C. y = 2/3x + 6.
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One equation that you could make is 5+2-(-3)
Yes it is :)
If there is an outlier on the lower end of the graph the mean will go down. If there is an outlier at the higher end of the graph the mean will go up.
