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3 years ago

Which of the following do indexes and scales have in common?

Mathematics

1 answer:

statuscvo [17]3 years ago

4 0

Answer:

c.They rank-order the units of analysis in terms of specific variables

Step-by-step explanation:

An index is a way of compiling one score from a variety of questions or statement that represents a belief, feeling or attitude.

Scales on the other hand measure levels of intensity at a variable level like how much a person agrees or disagrees with a particular statement.

The one thing common to both indexes and scales is that

They rank-order the units of analysis in terms of specific variables.

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An aquarium tank holds 475 liters of water. How much is this in gallons? Use the following conversion: 1 gallon is 3.8 liters.

Mrrafil [7]

$\bf \begin{array}{ccll}
liters&gallons\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
3.8&1\\
475&g
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3 years ago

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Answer and Step-by-step explanation:

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3 years ago

Kenya bought 5 pool noodles at $1.99 each, a unicorn

vampirchik [111]

Answer:74.04

Step-by-step explanation:

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3 years ago

Is this a parallelogram? If so, please explain why.

max2010maxim [7]

Answer:

the answer is no

Step-by-step explanation:

It only shows that one pair of lines are parallel but not both are. Parallelograms have two pairs of parallel lines.

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3 years ago

Read 2 more answers

Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

Formula

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

Calculation

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$

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2 years ago