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Misha Larkins [42]
2 years ago
11

2(3/5x+3). How would I get that answer

Mathematics
1 answer:
Airida [17]2 years ago
5 0

Answer: \frac{6}{5}x + 6

Step-by-step explanation:

       We will use the order of operations, also known as PEMDAS. See attached. Please note that we cannot do what is in the parentheses first because we have a variable, so we will distribute the 2 into it. Since this is an expression, I do not believe we can fully solve for x, but can only simplify.

       Given:

2(3/5x+3)

       Distribute:

2 * (3/5x) + (2 * 3)

6/5x + 6

       Answer:

\frac{6}{5}x + 6

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Can anyone help me with this math problem? Thank you.
pickupchik [31]

Step-by-step explanation:

Answer is in the picture.

4 0
3 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
Simplify x² + 3x + 2/X +1
kiruha [24]

Answer:

Step-by-step explanation:

It will be 7x+1

3 0
2 years ago
Describe the change in the graph of the parabola f(x) when it transforms into g(x) =
saw5 [17]

Answer:

  (d)  The parabola g(x) will open in the same direction of f(x), and the parabola will be wider than f(x).

Step-by-step explanation:

We assume you intend ...

  f(x) = equation of a parabola

  g(x) = 2/3·f(x)

Multiplying a function by a factor of 2/3 will cause it to be compressed vertically to 2/3 of its original height. When the function is a parabola, this has the effect of making it appear wider than before the compression.

__

The compression factor is positive, so points on the graph remain on the same side of the x-axis. The direction in which the graph opens is not changed.

The attachment shows parabolas that open upward and downward, along with the transformed version.

8 0
2 years ago
0.29 rounded? I need this for msth and quick!!
andreev551 [17]
.3 is that rounded to the nearest tenth
3 0
2 years ago
Read 2 more answers
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