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Reil [10]
3 years ago
11

(35 pts)Evaluate the reasoning provided by both students A and B and correct the errors Make sure to provide proper reasoning. O

nly answer if you know your answer is correct please.​

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0

Answer:

see the explanation

Step-by-step explanation:

we know that

A <u>Rational Number</u> is a number that can be made by dividing two integers

we have

\frac{\sqrt{2}}{8}

\sqrt{2} ----> is not a integer

so

The given number cannot be rewritten as the quotient of two integers

therefore

The given number is irrational

Student A is incorrect because is a irrational number and not all fractions are rational

Student B reasoning is incorrect, because there are fractions that have as numerator an irrational number and can be rational numbers

<em>example</em>

\frac{\sqrt{2}}{3\sqrt{2}}=\frac{1}{3} ----> is a rational number and the numerator is a irrational number

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What is the correct answer?
vovikov84 [41]

Answer:

84 units2

Step-by-step explanation:

First, you multiply 24 *7 = 168

Second, you divide 168 / 2 = 84

Lastly, have a great day!

5 0
2 years ago
3m-5p=12 solve for p
umka21 [38]
3m - 5p = 12

3m(-3m) -5p = (-3m)+ 12
-5p = -3m + 12
(-5)/-5p = (-5)/ (-3m + 12)
p = 3/5m + 12/-5
5 0
3 years ago
Read 2 more answers
Guys please please help me I’m begging u guys lol I need help please
Llana [10]

Answer:

What do you need help with?!?XD

Step-by-step explanation:


4 0
3 years ago
How much would $150 invested at 8% interest compounded continuously be worth after 17 years
Umnica [9.8K]

Answer:

Approximately $584.43

Step-by-step explanation:

Your formula is A=Pe^rt

A is what you're looking for, the amount

P is the principal aka what you put into the account: $150

e is the mathematical constant. You'd plug that into your calculator.

r is the rate, you'd put it into the equation as a decimal: 8%=.08

t is the time in years: 17

A=150e^.08x17 <em>you can plug this into your calculator</em>

A=$584.43

7 0
3 years ago
How do u find the product of 54.2and 10 to the second power
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