3(m-2)=5(m-4)
3m-6=5m-20
3m-5m=-20+6
-2m=-14
-m=-7
m=7
I hope this is what you need..
The slope of the line = 50
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15 ft = 180 inches
180/18 = 10
Therefore, each part is 10 inches long.
Let x be the number of minutes for
his normal walk
On the way to the airport, for the
2/5 (or 40%) of his route, his speed is twice faster. Hence, the number of x
should be divided to 2. The rest of the route (60%) was on his normal pace. The
total minutes is 6. The equation is:
0.4(x÷2) + 0.6x = 6
<span>Solving for x, the number of
minutes for his normal walk is 7.5 minutes.</span>
